Barium because this is have a greatest tendency.
Chlorine has the highest electron affinity or the greatest tendency to attract a shared pair of electrons in a covalent bond.
Fluorine require only one electron to fill its outer shell. Hence it has the greatest tendency to gain electrons than Al, Rb and I.
Type your answer here... Which is more likely to be reduced
Yes, beryllium is reactive due to its tendency to form bonds with other elements to achieve a more stable electron configuration. It readily reacts with oxygen in the air to form beryllium oxide, which is why it is often found in nature as compounds rather than in its pure form.
Metallic elements tend to donate electrons easily to form positive ions, which is why they are more likely to form ionic bonds. On the other hand, forming covalent bonds involves sharing electrons between atoms, which can be challenging for metallic elements due to their tendency to lose electrons easily. This property makes metallic elements less favorable for forming covalent bonds.
Chlorine has the highest electron affinity or the greatest tendency to attract a shared pair of electrons in a covalent bond.
You can tell that the beryllium atom is unstable because beryllium only has 2 valence electrons in its outer shell. An atom becomes stable when it has eight valence electrons, so in the case of beryllium it would have to lose those 2 electrons in its outer shell to become stable. often forming a cation with a 2+ charge.
The periods near the top, i presume because they have less shielding from other electrons in their orbitals, therefore there will be a larger nuclear pull so easier to attract electrons. Obviously a element with a full shell or 1 or 2 electrons in it isn't really going to gain electrons and Transition metals are weird. Hope this helps :)
Elements with one to two electrons in the outer energy level are typically the alkali metals (group 1) and alkaline earth metals (group 2) on the periodic table. These elements are highly reactive due to their tendency to lose these outer electrons to achieve a stable electron configuration. Examples include lithium, sodium, and beryllium.
Fluorine require only one electron to fill its outer shell. Hence it has the greatest tendency to gain electrons than Al, Rb and I.
The octet rule is the tendency of many chemical elements to have eight electrons in the valence shell.
Type your answer here... Which is more likely to be reduced
The octet rule is the tendency of many chemical elements to have eight electrons in the valence shell.
The metals have tendency to lose electrons. The elements of group-1,2 and 13 have tendency to form cations.
Elements become electropositive or electronegative based on their tendency to lose or gain electrons. Electropositive elements have a low electronegativity and readily lose electrons to form positive ions. Electronegative elements have a high electronegativity and tend to gain electrons to form negative ions.
Yes, beryllium is reactive due to its tendency to form bonds with other elements to achieve a more stable electron configuration. It readily reacts with oxygen in the air to form beryllium oxide, which is why it is often found in nature as compounds rather than in its pure form.
The octet rule is the tendency of many chemical elements to have eight electrons in the valence shell.