The hydrogen peroxide will decompose to give water and oxygen, potassium Iodide is acting as a catalyst
2H2O2(l)-------------> 2H2O(l) + O2(g)
When MnO2 is mixed with KI and 9 M sulfuric acid, a redox reaction occurs where MnO2 is reduced to Mn2+ and iodine in KI is oxidized to iodine gas. This reaction generates heat due to the exothermic nature of redox reactions, and a brownish gas of iodine is evolved. The manganese ions form a complex with iodine to create a brown solution.
When Pb(NO3)2 (lead nitrate) is mixed with KI (potassium iodide), a yellow precipitate of lead iodide (PbI2) is formed. This reaction can be represented by the equation: Pb(NO3)2 + 2KI -> 2KNO3 + PbI2.
The binary compound formed with potassium and iodine is called potassium iodide (KI).
When potassium iodide (KI) is mixed with sulfuric acid (H2SO4), the reaction will produce hydrogen iodide gas (HI) and potassium bisulfate (KHSO4) as products.
ki is added to liberate iodine gas . this liberated iodine gas was then titrated with sodium thiosulphate to give a permanent white precipitate. this white precipitate indicates the endpoint of the titration..
H2O2 + 2 KI --> 2 KOH + I2
There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2. The "slow step" is H2O2 + I- --> OI- + H2O The "fast step" is H2O2 + OI- --> H2O + I- O2 The overall is: 2 H2O2 --> 2H2O + O2
When MnO2 is mixed with KI and 9 M sulfuric acid, a redox reaction occurs where MnO2 is reduced to Mn2+ and iodine in KI is oxidized to iodine gas. This reaction generates heat due to the exothermic nature of redox reactions, and a brownish gas of iodine is evolved. The manganese ions form a complex with iodine to create a brown solution.
When Pb(NO3)2 (lead nitrate) is mixed with KI (potassium iodide), a yellow precipitate of lead iodide (PbI2) is formed. This reaction can be represented by the equation: Pb(NO3)2 + 2KI -> 2KNO3 + PbI2.
The binary compound formed with potassium and iodine is called potassium iodide (KI).
KI or potassium iodide. See the related link for more information.
When potassium iodide (KI) is mixed with sulfuric acid (H2SO4), the reaction will produce hydrogen iodide gas (HI) and potassium bisulfate (KHSO4) as products.
Literally, the correct formula for potassium and iodine at standard temperature and pressure would be " K and I2". The formula for the compound formed between potassium and iodine, however, is KI.
ban ki moon
ki is added to liberate iodine gas . this liberated iodine gas was then titrated with sodium thiosulphate to give a permanent white precipitate. this white precipitate indicates the endpoint of the titration..
The one that is ionic is KI, potassium iodide.
H2O2 The cation hydrogen has a charge of +1, and the anion peroxide has a charge of -2, so to balance peroxide's charge we would need two hydrogen atoms, as the net (total) charge of a compound must always be zero. I am, however, unsure if peroxide is indeed an anion, but the rest of the information is correct. Look it up if in doubt.