When NaHCO3 plus HCL reacted they forum two different substance that is H4CO3+NaCl, That is the balanced formula.
Possible precipitate of CaCO3. CaHCO3, NaHCO3, CaCl2 are soluble in water.
Nacl+Hcl+CaCO3
You need to know the amounts of reactants.
yes, it does react. It produces NaCl + CO2 + H2O so it looks like this... NaHCO3 + HCl ---> NaCl + CO2 + H2O
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
2 NaHCO3 plus energy --> Na2CO3 plus CO2 plus H2O
Nacl+Hcl+CaCO3
You need to know the amounts of reactants.
yes, it does react. It produces NaCl + CO2 + H2O so it looks like this... NaHCO3 + HCl ---> NaCl + CO2 + H2O
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
NaHCO3 + HCl --> NaCl + CO2 + H2O Products are a salt, carbon dioxide gas and water.
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
2 NaHCO3 plus energy --> Na2CO3 plus CO2 plus H2O
The dissociation is:NaHCO3-------------Na+ + (HCO3)-
Let's see.NaHCO3 + HCl --> NaCl + CO2 + H2OCarbon dioxide, for sure!
Baking soda is sodium bicarbonate, NaHCO3. Sodium bicarbonate and hydrochloric acid, HCl, react to form sodium chloride, NaCl and carbonic acid, H2CO3. NaHCO3 + HCl ---> NaCl + H2CO3
NaHCo3
The reaction is: NaHCO3 + HCl = NaCl + CO2 + H2O The correct name of HCl is hydrochloric acid.