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What products do you get when CaCl2 plus NaHCO3?
When CaCl2 reacts with NaHCO3, the products formed are CaCO3 (calcium carbonate), NaCl (sodium chloride), and H2O (water).
What is the balanced equation when sodium bicarbonate reacts with hydrochloric acid?
The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl) is: NaHCO3 + HCl → NaCl + H2O + CO2
What mass of NaHCO3 would be needed to neutralize a spill consisting of 12.5 mL of 5.0 M HCl?
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
Is salicylic acid miscible in Naoh nahco3 and Hcl?
Salicylic acid is soluble in NaOH and insoluble in NaHCO3 and HCl. In NaOH, salicylic acid can form a salt through neutralization. In NaHCO3 and HCl, salicylic acid remains as a solid due to its low solubility in these solutions.
What does hydrochloric acid plus sodium bicarbonate equals?
Hydrochloric acid (HCl) plus sodium bicarbonate (NaHCO3) will produce water, carbon dioxide gas, and sodium chloride (table salt) when they react. The reaction can be represented by the following equation: HCl + NaHCO3 → H2O + CO2 + NaCl.
What products do you get when CaCl2 plus NaHCO3?
When CaCl2 reacts with NaHCO3, the products formed are CaCO3 (calcium carbonate), NaCl (sodium chloride), and H2O (water).
What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
What is the balanced equation when sodium bicarbonate reacts with hydrochloric acid?
The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl) is: NaHCO3 + HCl → NaCl + H2O + CO2
What mass of NaHCO3 would be needed to neutralize a spill consisting of 12.5 mL of 5.0 M HCl?
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
Is salicylic acid miscible in Naoh nahco3 and Hcl?
Salicylic acid is soluble in NaOH and insoluble in NaHCO3 and HCl. In NaOH, salicylic acid can form a salt through neutralization. In NaHCO3 and HCl, salicylic acid remains as a solid due to its low solubility in these solutions.
What does hydrochloric acid plus sodium bicarbonate equals?
Hydrochloric acid (HCl) plus sodium bicarbonate (NaHCO3) will produce water, carbon dioxide gas, and sodium chloride (table salt) when they react. The reaction can be represented by the following equation: HCl + NaHCO3 → H2O + CO2 + NaCl.
What happen when sodium bicarbonate reacts with hidrochloric acid?
NaHCO3 + HCl --> NaCl + CO2 + H2O Products are a salt, carbon dioxide gas and water.
Reaction equation of sodium hydrogencarbonate with hydrochloric acid?
The reaction equation for sodium hydrogencarbonate (NaHCO3) with hydrochloric acid (HCl) is: NaHCO3 + HCl → NaCl + H2O + CO2 This reaction produces sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2) as products.
Would NaHCO3 react with HCl?
yes, it does react. It produces NaCl + CO2 + H2O so it looks like this... NaHCO3 + HCl ---> NaCl + CO2 + H2O
How many moles of hcl are needed to react with 0.35 g of NAHCO3?
The answer to the conversion is that 35.0 grams of hydrochloride (HCL) equals 0.76 moles. The conversion rate is 35.0 grams divided by 46 gram per mole. A mole is the molecular weight of a substance.
What is the balanced equation for hno3 plus nahco3-nano3 plus H2O plus CO2?
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
What is an exapmple of a chemical change for baking soda?
Baking soda is sodium bicarbonate, NaHCO3. Sodium bicarbonate and hydrochloric acid, HCl, react to form sodium chloride, NaCl and carbonic acid, H2CO3. NaHCO3 + HCl ---> NaCl + H2CO3
