Lets start with the reaction of methane fully reacting with oxygen:
CH4 + 2 O2 --> CO2 + 2 H2O
The ratio CH4:O2 is 1:2
So 0.1 mole of methane can potentially react with 0.2 mole of oxygen.
Seeing as we only have 0.1 mole oxygen we know that we have excess of methane.
Because of the lack of oxygen the methane can form carbonmonoxide (CO) instead of CO2.
(if someone knows the composition of the final product, please add here. As far as i know, you cant predict the CO:CO2 ratio.)
The reactants when methane burns in oxygen are methane and oxygen. The products are CO2, water and heat about 890 Kj/mole is given out. The equation is : CH4(g) + 2O2 _______> CO2 + 2H2O + Heat (-890 Kj/mole) When one mole of methane gas reacts with (burns in) 2 moles of oxygen gas we get 1 mole of carbon dioxide and 2 moles of water and 890 Kilo joules of heat is released. This reaction is exothermic as heat is released and a combustion reaction as methane gas is burned in free supply oxygen not limited supply otherwise carbon monoxide (CO) will be formed. Hope that helped you out. :-D
890 kJ of energy are released when I mole of methane (16 g) is completely burned in oxygen.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
The balanced chemical equation for the reaction is: CH4 + 2O2 -> CO2 + 2H2O. From this, we can see that 1 mole of methane produces 2 moles of water. The molar mass of water is 18 g/mol, so the mass of water produced would be 36 g.
Natural gas + Oxygen -> Carbon dioxide + Watereg: CH4 + 2O2 -> CO2 + 2H2OWhere complete combustion of methane (CH4, a natural gas) is achieved.After stating what precisely is meant by 'natural gas' (could be methane o.s.e.) then, in words, it could be something like:"One mole of the natural gas 'methane' reacts with two moles of oxygen to form one mole of carbon dioxide and two moles of water"Well, a simple chemical notation is easier and less ambiguous!
The reactants when methane burns in oxygen are methane and oxygen. The products are CO2, water and heat about 890 Kj/mole is given out. The equation is : CH4(g) + 2O2 _______> CO2 + 2H2O + Heat (-890 Kj/mole) When one mole of methane gas reacts with (burns in) 2 moles of oxygen gas we get 1 mole of carbon dioxide and 2 moles of water and 890 Kilo joules of heat is released. This reaction is exothermic as heat is released and a combustion reaction as methane gas is burned in free supply oxygen not limited supply otherwise carbon monoxide (CO) will be formed. Hope that helped you out. :-D
1 mole of methane (CH4) reacts with 2 moles of oxygen (O2) to produce 1 mole of carbon dioxide (CO2) and 2 moles of water (H2O). The reaction is balanced with respect to the number of atoms of each element on both sides of the reaction equation.
890 kJ of energy are released when I mole of methane (16 g) is completely burned in oxygen.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
The balanced chemical equation for the reaction is: CH4 + 2O2 -> CO2 + 2H2O. From this, we can see that 1 mole of methane produces 2 moles of water. The molar mass of water is 18 g/mol, so the mass of water produced would be 36 g.
Natural gas + Oxygen -> Carbon dioxide + Watereg: CH4 + 2O2 -> CO2 + 2H2OWhere complete combustion of methane (CH4, a natural gas) is achieved.After stating what precisely is meant by 'natural gas' (could be methane o.s.e.) then, in words, it could be something like:"One mole of the natural gas 'methane' reacts with two moles of oxygen to form one mole of carbon dioxide and two moles of water"Well, a simple chemical notation is easier and less ambiguous!
1) First find the number of moles of methane in 27.8 g using the molar mass.See the Related Question to the left of this answer "How do you convert from grams to moles and also from moles to grams?" to do that.2) Then write the balanced reaction. Methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). See the related question "How do you balance a chemical reaction?" to do that.3) That will tell you the ratio of moles of methane to moles of oxygen (it will be 2 to 1). So from Part 1, multiply the number of moles of methane by 2 to get moles of oxygen. Then, use the Ideal Gas Law to find out how many liters that will take up at STP. Use the Related Question link "How do you solve Ideal Gas Law problems?" to do that.
0.95 - 0.954
To calculate the moles of carbon dioxide, we first need to determine the number of moles of oxygen in 16g. Using oxygen's molar mass of 16 g/mol, we find that there is 1 mole of oxygen in 16g. Since one mole of oxygen reacts with one mole of carbon dioxide in the balanced equation, there will also be 1 mole of carbon dioxide formed.
Each molecule of methane contains one carbon atom, as shown by the formula for methane, CH4. Therefore, the number of carbon atoms in one mole of methane is the same as Avogadro's Number, about 6.022 X 1023.
Moles of methane. No half molecules, I think! 2.50 moles methane (1 mole C/1 mole CH4)(6.022 X 1023/1 mole C) = 1.51 X 1024 molecules of carbon --------------------------------------------
False, They contain the same number of molecules, not the same number of atoms. H2O contains 3 atoms, so in 1 mole of water there are 6.022*10^23 * 3 = 1.81*10^24 atoms. CH4 contains 5 atoms, so in 1 mole of methane there are 6.022*10^23 * 5 =3.01*10^24 atoms.