Lets start with the reaction of methane fully reacting with oxygen:
CH4 + 2 O2 --> CO2 + 2 H2O
The ratio CH4:O2 is 1:2
So 0.1 mole of methane can potentially react with 0.2 mole of oxygen.
Seeing as we only have 0.1 mole oxygen we know that we have excess of methane.
Because of the lack of oxygen the methane can form carbonmonoxide (CO) instead of CO2.
(if someone knows the composition of the final product, please add here. As far as i know, you cant predict the CO:CO2 ratio.)
The reactants when methane burns in oxygen are methane and oxygen. The products are CO2, water and heat about 890 Kj/mole is given out. The equation is : CH4(g) + 2O2 _______> CO2 + 2H2O + Heat (-890 Kj/mole) When one mole of methane gas reacts with (burns in) 2 moles of oxygen gas we get 1 mole of carbon dioxide and 2 moles of water and 890 Kilo joules of heat is released. This reaction is exothermic as heat is released and a combustion reaction as methane gas is burned in free supply oxygen not limited supply otherwise carbon monoxide (CO) will be formed. Hope that helped you out. :-D
Look for the reaction equation: CH4(g) +2O2(g) --> CO2(g) + 2H2O(g) So it is 1:1 for methane:carbon dioxide so there is 1 mole of CO2 formed and hence 6.022 x 1023 molecules.
890 kJ of energy are released when I mole of methane (16 g) is completely burned in oxygen.
If by "air" you mean oxygen, then the mole ratio can by found by balancing a reaction equation. CH4 + 202 -> CO2 + 2H2O The ratio is 1:2.
Natural gas + Oxygen -> Carbon dioxide + Watereg: CH4 + 2O2 -> CO2 + 2H2OWhere complete combustion of methane (CH4, a natural gas) is achieved.After stating what precisely is meant by 'natural gas' (could be methane o.s.e.) then, in words, it could be something like:"One mole of the natural gas 'methane' reacts with two moles of oxygen to form one mole of carbon dioxide and two moles of water"Well, a simple chemical notation is easier and less ambiguous!
The reactants when methane burns in oxygen are methane and oxygen. The products are CO2, water and heat about 890 Kj/mole is given out. The equation is : CH4(g) + 2O2 _______> CO2 + 2H2O + Heat (-890 Kj/mole) When one mole of methane gas reacts with (burns in) 2 moles of oxygen gas we get 1 mole of carbon dioxide and 2 moles of water and 890 Kilo joules of heat is released. This reaction is exothermic as heat is released and a combustion reaction as methane gas is burned in free supply oxygen not limited supply otherwise carbon monoxide (CO) will be formed. Hope that helped you out. :-D
Look for the reaction equation: CH4(g) +2O2(g) --> CO2(g) + 2H2O(g) So it is 1:1 for methane:carbon dioxide so there is 1 mole of CO2 formed and hence 6.022 x 1023 molecules.
6.02x10^23 molecules of CO2 and 1.2x10^24 molecules of H2O are produced.
890 kJ of energy are released when I mole of methane (16 g) is completely burned in oxygen.
If by "air" you mean oxygen, then the mole ratio can by found by balancing a reaction equation. CH4 + 202 -> CO2 + 2H2O The ratio is 1:2.
Natural gas + Oxygen -> Carbon dioxide + Watereg: CH4 + 2O2 -> CO2 + 2H2OWhere complete combustion of methane (CH4, a natural gas) is achieved.After stating what precisely is meant by 'natural gas' (could be methane o.s.e.) then, in words, it could be something like:"One mole of the natural gas 'methane' reacts with two moles of oxygen to form one mole of carbon dioxide and two moles of water"Well, a simple chemical notation is easier and less ambiguous!
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
6 molecules of oxygen are needed to react with 3 methane molecules as one molecule of oxygen ( O2) are needed for methane gas.
0.95 - 0.954
I mole - 16g of methane is 1 mole. At STP it would occupy 22.4 liters
Methane and oxygen react according to the equation:CH4 + 2O2 -->CO2 + 2H2O Thus 1 mole of methane produces 2 moles of water. 25.9 g of water is 25.9/18 moles = 1.44 moles.So we must have started with 0.72 moles of methane, which is 0.72 x 16 g= 11.51 g of methane.
All the combustion reactions I know of are exothermic because heat is released instead of absorbed. And propane gives more energy than methane cause it has more Cs and Hs to react with Oxygen, so one mole of propane will react more and form more product than one mole of methane and giving out more energy. All the combustion reactions I know of are exothermic because heat is released instead of absorbed. And propane gives more energy than methane cause it has more Cs and Hs to react with Oxygen, so one mole of propane will react more and form more product than one mole of methane and giving out more energy.