Lead poisoning. Symptoms include abdominal pain and spasms, nausea, vomiting, headache. Acute poisoning can lead to muscle weakness, "lead line" on the gums, metallic taste, definite loss of appetite, insomnia, dizziness, high lead levels in blood and urine with shock, coma and death in extreme cases. Nitrates entering the body by any route (ingestion, inhalation, or absorption), can cause headache vomiting, dizziness, cyanosis, decreased blood pressure, and possibly respiratory paralysis.
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
It depends on the conentration, did a test today with several nitrates (incl. lead nitrate) and they were all yellow/orange...
When lead nitrate is mixed with sodium iodide, a solid precipitate of lead iodide is formed along with sodium nitrate. This reaction is a double displacement reaction where the cations of the two compounds switch partners to form the products. Lead iodide is a yellow precipitate that can be easily observed in the reaction mixture.
You can separate lead nitrate from a lead nitrate solution by adding a soluble salt like sodium chloride, which will cause lead chloride to precipitate out as a solid. The lead chloride can then be filtered out from the solution, leaving you with the lead nitrate solution separated from the lead chloride.
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
It depends on the conentration, did a test today with several nitrates (incl. lead nitrate) and they were all yellow/orange...
When lead nitrate is mixed with sodium iodide, a solid precipitate of lead iodide is formed along with sodium nitrate. This reaction is a double displacement reaction where the cations of the two compounds switch partners to form the products. Lead iodide is a yellow precipitate that can be easily observed in the reaction mixture.
You can separate lead nitrate from a lead nitrate solution by adding a soluble salt like sodium chloride, which will cause lead chloride to precipitate out as a solid. The lead chloride can then be filtered out from the solution, leaving you with the lead nitrate solution separated from the lead chloride.
The chemical formula of lead(II) nitrate is Pb(NO3)2; also exist the lead(IV) nitrate but not the lead(III) nitrate.
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.
PbNO3 Lead (I) Nitrate Yes
Silver nitrate and lead nitrate do not react, so there would be no precipitate.
A single displacement reaction occurs, where aluminum displaces lead from the lead nitrate solution to form aluminum nitrate and lead metal. This reaction will produce a silver-like appearance on the surface of the aluminum due to the deposition of lead metal.
When silver nitrate is mixed with lead, a solid white precipitate of lead(II) nitrate is formed along with silver metal. This reaction is a displacement reaction where the more reactive silver displaces the less reactive lead from the compound.
The products will be lead hydroxide and sodium nitrate