it freezes
The expression for specific heat is Q = mc(delta T) where Q is the heat added, c is the specific heat, m is the mass, and delta T is the change in temperature in degrees C. Specific heat is the amount of heat per unit of mass needed to raise the temperature by 1 degree C. The specific heat of water is 1 cal/gram degree C = 4.186 joule/gram degree C. Water has a higher specific heat than most common substances.
The specific heat capacity of water is 4.18 J/g°C. Therefore, it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
The specific heat capacity of water is 4.18 J/g°C. To raise the temperature of one cubic centimeter of water by one degree Celsius, you would need to use the density of water (1 g/cm³) to calculate the mass (1 gram), and then use the specific heat capacity to find the energy required: 4.18 J/g°C * 1 g * 1°C = 4.18 Joules.
The amount of cooling required to lower the temperature of a substance by one degree Celsius is known as the substance's specific heat capacity. It depends on the substance's properties and can be measured in joules per gram per degree Celsius (J/g°C) or in joules per kilogram per degree Celsius (J/kg°C).
Water has a high specific heat capacity due to hydrogen bonding between its molecules, which allows it to absorb and release heat energy without large changes in temperature. The specific heat capacity of water is 1.00 cal/g°C, or 4.185 J/g°C, meaning it takes 1 calorie of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
There are 3.966 BTU in a kilocalorie (kcal), and 1 kcal raises 1 kg of water 1 degree C, but to work through it:1 BTU raises 1 pound of water 1 degree F, and 1 kg = 2.20 pounds, therefore:2.20 BTU raises 1 kg of water 1 degree F, and 1 litre of water weighs 1 kg (basically), therefore:2.20 BTU raises 1 litre of water 1 degree F, and a 1 degree change in F equals 5/9 degree C, therefore:2.20 BTU raises 1 litre of water 5/9 degree C, therefore:3.96 BTU raises 1 litre of water 1 degree C.
It takes 1000 calories to heat 1 litre of water 1 degree C.
Depends on how high you want to raise the gram of water ;).
Choose a vacuum pump with a 29.75 hg that makes water boil 1 degree C. The typical boiling point of water is hundred degrees Celsius.
It takes approximately 1 kilowatt-hour (kWh) of energy to raise 1 liter of water by 1 degree Celsius. This is a common measure of energy for heating water in many applications.
Energy required to raise 1 gramme of water by 1 degree C = 1 calorie also, 1 calorie = 4.186 Joules
at standard pressure, the vapor condenses to liquid water at 100 C
The temperature 1°C is warmer, above water's freezing point on the Celsius scale (0°C).The temperature 1°F is well below freezing on the Fahrenheit scale (32°F).The equivalent temperature to 1°F is -17.22°C.---The two temperature scales have different "starting points" - zero in Celsius is the freezing point of water, while zero in Fahrenheit is the fralty water). So 1° Celsius is above freezing while 1° Fahrenheit is below freezing, the freezing point of pure water being 0°C but 32° F.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
The expression for specific heat is Q = mc(delta T) where Q is the heat added, c is the specific heat, m is the mass, and delta T is the change in temperature in degrees C. Specific heat is the amount of heat per unit of mass needed to raise the temperature by 1 degree C. The specific heat of water is 1 cal/gram degree C = 4.186 joule/gram degree C. Water has a higher specific heat than most common substances.
The answer is 2 calories.
Roughly 4.18400 joules Raising 1 gram of water 1 degree c requires 1 calorie (the definition of calorie includes the actual starting temperature, I think something like 3 degrees celsius). 1 calorie = 4.18400 joules