it results in the formation of phenyl-azo-2-naphthol, an azo dye which is orange-red in colour
To synthesize acetophenone from benzene, you just need to add the aldehyde to the benzene ring. This can be done via a Friedel-Crafts acylation. The reagents are an acid chloride (acetyl chloride in this case) and AlCl3 (stoichiometric).
because change happens
it's a slfonation and made benzene sulfonyl chloride
Four examples of a molecule: water (H2O), hydrogen chloride (HCl), fluorine (F2), benzene (C6H6).
Use acetic anhydride as reagent. The reaction will undergo nucleophilic addition and the reagent will attach to the amine group. Half of the reagent will become the leaving group and one H of the amine group in the reactant will leave with the reagent. The product will be the benzene ring with an amine, carbonyl, methyl attached.
Sodium chloride is not soluble in benzene.
The full form of BHC is BENZENE HEXA CHLORIDE.
Benzene is nonpolar, so its molecules do not have any strong attraction to sodium chloride, which is ionic.
vinylogous?
To synthesize acetophenone from benzene, you just need to add the aldehyde to the benzene ring. This can be done via a Friedel-Crafts acylation. The reagents are an acid chloride (acetyl chloride in this case) and AlCl3 (stoichiometric).
This is an example of a Friedel-Crafts acylation. One hydrogen from the benzene is replaced by the acetyl portion of the acetyl chloride and the hydrogen and chloride from the benzene and acetyl chloride respectively combine to form HCl. Please see the link.
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Toluene + HNO3/H2SO4 --> p-nitrotoluene (para directed nitration) p-nitrotoluene + Zn/HCl --> p-aminotoluene (changing NO2 to NH2 by reduction) p-aminotoluene +Br2 --> bromination ortho to NH2 Remove NH2 via diazonium salt and decomposition with 1) HONO (which is NaNO2+HCl), 2) H3PO2 for the final product.
Hexane is non polar compound and benzene also non polar compound so non polar comp's soluble in non polar reagents. But sodium chloride is ionic so does nt dissolve benzene in it
No, NaCL is polar, benzen is non-polar.
because change happens
One can synthesize this compound starting with benzene or with p-bromoaniline. If you are starting with p-bromoaniline, which is readily available, convert it into the corresponding diazonium salt, and then react it with cuprous chloride. This will give the compound. Make sure the temperatures are low for the reagents or else the phenol will be formed. Extraction in diethyl ether, followed by NaOH wash will give a purer extract. Purification by sublimation will allow the isolaion of the product, BE AWARE OF DIAZONIUM COUPLING REACTIONS AND KEEP THE REAGENTS COLD!