No, they do not react.
H2(g) + Br2(g) → 2HBr(g)
Hydrogen and bromine react to form hydrogen bromide (HBr), which is a colorless gas at room temperature and is a corrosive acid when dissolved in water.
Yes, the products are hydrogen sulfide and iron II bromide. 2HBr + FeS --> FeBr2 + H2S
Ethyl bromide react with Grignard reagentCH3-CH2-Br + CH3-Mg_Br
A common mechanism is the hydrogenation of a double bond, which would produce propane
Hydrogen does not react with water
H2(g) + Br2(g) → 2HBr(g)
Hydrogen and bromine react to form hydrogen bromide (HBr), which is a colorless gas at room temperature and is a corrosive acid when dissolved in water.
Yes, the products are hydrogen sulfide and iron II bromide. 2HBr + FeS --> FeBr2 + H2S
Ethyl bromide react with Grignard reagentCH3-CH2-Br + CH3-Mg_Br
A common mechanism is the hydrogenation of a double bond, which would produce propane
HBR doesn't react with Propane, but it does with Propene. The product is either 1-bromo propane(minor product) or 2-bromo propane(major product). To determine which product will be the major product, use the Markovnikov's rule.
Gold does not react with sodium bromide under normal conditions. Gold is a noble metal and is relatively unreactive with other elements, including sodium bromide.
When potassium bromide and sulfuric acid react, potassium sulfate and hydrogen bromide gas are produced. This reaction is characterized by the liberation of hydrogen bromide gas, which can be identified by its pungent odor and may form a white mist when exposed to moist air due to its reaction with water vapor.
Bromine reacts with hydrogen to form hydrogen bromide (HBr). The reaction is exothermic and proceeds rapidly to give a colorless gas. The reaction can be represented as follows: Br2 + H2 -> 2HBr.
Iodine and lithium bromide do not react with each other. However, iodine can form a complex with lithium ions in a solution containing lithium bromide.
When aqueous bromide ions react with chlorine gas, bromide ions are oxidized to form bromine gas. This reaction typically occurs in the presence of an acid as a catalyst. The overall reaction can be represented by the equation: 2Br^-(aq) + Cl2(g) -> Br2(g) + 2Cl^-(aq)