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Mg3(Po4)2
Mg(ClO4)2 with molar mass 223.206 g/mol
Hydrogen cyanide, HCN, has a molar mass of 27.03g/mol.
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
The gram formula unit mass of magnesium chloride is 95.21. Therefore, 21.2g of magnesium chloride make up 21.2/95.21 or 0.223 formula units, to the justified number of significant digits.
95.21 amu
The mass is 991,5 g.
Mg3(Po4)2
The gram formula mass of the less hydrated stable form of magnesium nitrate, Mg(NO3)2.2 H2O, is 184.35. This formula shows that each formula unit contains one magnesium atom. The gram atomic mass of magnesium is 24.305. Therefore, the percentage by mass of magnesium in this magnesium nitrate dihydrate is 100(24.305/184.35) or 13.038 %, to the justified number of significant digits.
Mg(ClO4)2 with molar mass 223.206 g/mol
The formula of magnesium sulphide is MgS, showing that a formula unit has one atom of each element. The gram atomic mass of magnesium is 24.305 and that of sulphur is 32.06. Therefore, when magnesium and sulphur are present in equal amounts by mass, sulphur is the limiting reactant. 1.0/32.06 or 0.031 moles of sulphur atoms are present. Therefore, the maximum amount of MgS that can result from reaction is 0.031 formula units of MgS. The gram formula mass of MgS is 56.365, so that 0.031 formula units of MgS will have a mass of 1.7 grams, to the justified number of significant digits.
191.19 amu
Hydrogen cyanide, HCN, has a molar mass of 27.03g/mol.
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
159.19 - 159.23
CaCl2 = MM(Ca) + 2*MM(Cl) = 40 + 35.5 * 2 =111
The gram formula unit mass of magnesium chloride is 95.21. Therefore, 21.2g of magnesium chloride make up 21.2/95.21 or 0.223 formula units, to the justified number of significant digits.