Dipole-dipole and dispersion
The intermolecular force in BF3 is London dispersion forces. This is because BF3 is a nonpolar molecule, so the only intermolecular force it experiences is the temporary weak attraction between temporary dipoles.
The reaction between NaNH2 and CH3I proceeds through a nucleophilic substitution reaction, where the NaNH2 acts as a nucleophile attacking the carbon atom in CH3I, leading to the formation of a new compound and the release of sodium iodide as a byproduct.
The strongest intermolecular force present in hydrogen bromide (HBr) is dipole-dipole interaction.
In the case of a covalent bond, the intramolecular force is stronger than the intermolecular force. The covalent bond holds atoms together within a molecule, while intermolecular forces are weaker interactions between molecules.
To determine the strongest intermolecular force in a substance, you need to consider the types of molecules present. Look for hydrogen bonding, which is the strongest intermolecular force. If hydrogen bonding is not present, then consider dipole-dipole interactions and London dispersion forces in determining the strength of intermolecular forces.
Formula: CH3I
intermolecular force
This is an intermolecular force.
Gravity!
Boiling point is a property not a force; but a high boiling point indicate a strong intermolecular force.
Intermolecular attraction
The intermolecular force in Ar (argon) is London dispersion forces, which are the weakest type of intermolecular force. This force is caused by temporary fluctuations in electron distribution around the atom, leading to temporary dipoles.
Intramolecular forces are not intermolecular forces !
Formula: CH3I
The intermolecular force in BF3 is London dispersion forces. This is because BF3 is a nonpolar molecule, so the only intermolecular force it experiences is the temporary weak attraction between temporary dipoles.
The reaction between NaNH2 and CH3I proceeds through a nucleophilic substitution reaction, where the NaNH2 acts as a nucleophile attacking the carbon atom in CH3I, leading to the formation of a new compound and the release of sodium iodide as a byproduct.
Intermolecular forces shown by the dotted lines not by strong covalent bonds.