0
What else can I help you with?
CH3I plus CH3COONa equals?
The reaction between CH3I and CH3COONa would result in the formation of CH3COCH3 (acetone) and NaI. This is known as a nucleophilic substitution reaction where the iodine in CH3I is replaced by the acetate group from CH3COONa.
What intermolecular force is CH3I?
CH3I exhibits dipole-dipole interactions due to the presence of a polar covalent bond between carbon and iodine. Additionally, it may also experience some weak dispersion forces.
What will be the product of the reaction of ethanol and NaOH and iodine?
The reaction of ethanol with NaOH and iodine will yield iodoethane (ethyl iodide) as the product. The alcohol group in ethanol will be replaced by the iodine atom in the presence of NaOH.
Is CH3I polar or nonpolar?
CH3I is polar due to the difference in electronegativity between carbon, hydrogen, and iodine atoms. The iodine atom is more electronegative than carbon and hydrogen, creating an uneven distribution of electron density within the molecule, resulting in a net dipole moment.
What type of bonding CH3I?
CH3I exhibits covalent bonding, with the carbon and hydrogen atoms sharing electrons to form bonds. The iodine atom is connected via a polar covalent bond, in which the electrons are not shared equally between the carbon and iodine atoms.
CH3I plus CH3COONa equals?
The reaction between CH3I and CH3COONa would result in the formation of CH3COCH3 (acetone) and NaI. This is known as a nucleophilic substitution reaction where the iodine in CH3I is replaced by the acetate group from CH3COONa.
Is CH3I iodoformed?
Yes, CH3I can undergo iodoform reaction when treated with a strong base like NaOH to form iodoform (CHI3) along with other byproducts.
What is the chemical formula for Iodimethane?
Formula: CH3I
What intermolecular force is CH3I?
CH3I exhibits dipole-dipole interactions due to the presence of a polar covalent bond between carbon and iodine. Additionally, it may also experience some weak dispersion forces.
What is the chemical formula for idomethane?
Formula: CH3I
What will be the product of the reaction of ethanol and NaOH and iodine?
The reaction of ethanol with NaOH and iodine will yield iodoethane (ethyl iodide) as the product. The alcohol group in ethanol will be replaced by the iodine atom in the presence of NaOH.
Is CH3I polar or nonpolar?
CH3I is polar due to the difference in electronegativity between carbon, hydrogen, and iodine atoms. The iodine atom is more electronegative than carbon and hydrogen, creating an uneven distribution of electron density within the molecule, resulting in a net dipole moment.
What type of bonding CH3I?
CH3I exhibits covalent bonding, with the carbon and hydrogen atoms sharing electrons to form bonds. The iodine atom is connected via a polar covalent bond, in which the electrons are not shared equally between the carbon and iodine atoms.
What is the molecular geometry for CH3I?
Since there is 4 electron domains which are all single bonds without any lone pairs, the molecular geometry is tetrahedral.
What is esterification of sugar?
Probably when you take a sugar with alcohol components (-OH), turn them into O- ions by using a basic conditions (say NaOH) and then alkalizing them to form esters (say CH3I). That would replace all alcohols with (-OCH3 esters). "esterification of sugars"
What are 2 substances that contain the element iodine?
Iodine is in: Iodomethane (CH3I) that is produced by the marine environment, by microbial activity in rice paddies and in Potassium iodide (KI) a very soluble salt.
Is it possible for an alkyl halide to undergo sn1 and also sn2 reactions?
Yes an alkyl halide can undergo both Sn1 and Sn2 reactions - it just depends on what kind of alkyl halide it is. Methyl halides such as CH3Br/CH3Cl/CH3I, etc. are most suitable for Sn2 reactions because they are less sterically hindered by R-groups (they are not "bulky"). This allows for easy attack by the nucleophile. Primary alkyl halides (RCH2X) are also most suitable for Sn2 because of the same reason above Secondary alkyl halides can undergo both Sn1 and Sn2 reactions, this depends on other factors such as solvent and leaving group and nucleophile. If the solvent is polar aprotic, the reaction will go Sn2, if polar protic - Sn1. Tertiary alkyl halides (alkyl halides with 4 r-groups) do not go Sn2 because they are bulky and the R-groups stabilize the carbocation by hyperconjugation and inductive effect.
