Yes, CH3I can undergo iodoform reaction when treated with a strong base like NaOH to form iodoform (CHI3) along with other byproducts.
Formula: CH3I
Formula: CH3I
The reaction between NaNH2 and CH3I proceeds through a nucleophilic substitution reaction, where the NaNH2 acts as a nucleophile attacking the carbon atom in CH3I, leading to the formation of a new compound and the release of sodium iodide as a byproduct.
The reaction between CH3I and CH3COONa would result in the formation of CH3COCH3 (acetone) and NaI. This is known as a nucleophilic substitution reaction where the iodine in CH3I is replaced by the acetate group from CH3COONa.
CH3I exhibits dipole-dipole interactions due to the presence of a polar covalent bond between carbon and iodine. Additionally, it may also experience some weak dispersion forces.
CH3I is polar due to the difference in electronegativity between carbon, hydrogen, and iodine atoms. The iodine atom is more electronegative than carbon and hydrogen, creating an uneven distribution of electron density within the molecule, resulting in a net dipole moment.
CH3I exhibits covalent bonding, with the carbon and hydrogen atoms sharing electrons to form bonds. The iodine atom is connected via a polar covalent bond, in which the electrons are not shared equally between the carbon and iodine atoms.
Since there is 4 electron domains which are all single bonds without any lone pairs, the molecular geometry is tetrahedral.
The reaction of ethanol with NaOH and iodine will yield iodoethane (ethyl iodide) as the product. The alcohol group in ethanol will be replaced by the iodine atom in the presence of NaOH.
Probably when you take a sugar with alcohol components (-OH), turn them into O- ions by using a basic conditions (say NaOH) and then alkalizing them to form esters (say CH3I). That would replace all alcohols with (-OCH3 esters). "esterification of sugars"
Iodine is in: Iodomethane (CH3I) that is produced by the marine environment, by microbial activity in rice paddies and in Potassium iodide (KI) a very soluble salt.
Well there is no acid, I repeat N O ! A C I D ! (cf. discussion page), with the formula HCI (with elements H, C, and I) because:HCI is a chemically impossible compound, or at least never been synthesizedIf it where then it wouldn't be an acid, rather a iodine-substituted hydrocarbon H(4-n)CI(n) with n = 1, 2 or 3 which all are not water soluble.The chemical name of this NONexisting compound CHI would have been mono-iodine methane (CH3I is possible) or tri-iodine methane (CHI3 is possible).