C6H14 - dispersion forces
H2O - hydrogen bonding, dipole, dispersion
HCHO - dipole, dispersion
C6H5OH - hydrogen bonding, dipole, dispersion
C6h14 + 13o2 ---> 7h2o + 6co2 The website keeps making correctinos to my capitalization of the elements, but this is the balanced equation.
C6H14 is a non-electrolyte. Non-electrolytes do not dissociate into ions when dissolved in water and therefore do not conduct electricity.
No. The empirical formula of a substance is the formula in which each atomic symbol has the lowest possible subscript that gives the correct ratio between atoms for the compound as a whole. For C6H12, the empirical formula is CH2, but for C6H14, the empirical formula is C3H7.
C6h14
The compound C6H14 with a base peak at m/z 43 is likely to be hexane. Hexane has a molecular formula of C6H14 and a base peak at m/z 43 due to the fragmentation pattern of the molecule during ionization in mass spectrometry.
The boiling point of any compound is determined by how much energy it takes to break apart the intermolecular bonds. C6H14 has very low intramolecular forces compared to the polar bonds of another compound, such as water.
Yes, it does C6H14 is the saturated form called hexane.
no
C6H14 is an alkane. Alkanes have the general formula CnH2n+2, where n represents the number of carbon atoms and only single bonds are present between carbon atoms. CH2O does not fit this general formula for alkanes as it contains oxygen and is not a hydrocarbon. C3H4 is also not an alkane as it does not have the general formula CnH2n+2.
the chemical formula C6H14 has 5 compounds
C6h14 + 13o2 ---> 7h2o + 6co2 The website keeps making correctinos to my capitalization of the elements, but this is the balanced equation.
YES
C6h14
Because alkanes follow the formula CnH2n+2 as 6*2+2=14, we can conclude c6h14 is an alkane
The different elements of C6H14 are carbon and hydrogen. If by different elements you mean isomers then they would be:Hexane2-methylpentane3-methylpentane2,2-dimethylbutane2,3-dimethylbutane
The molecular formula of all the hexanes is C6H14. (Remember the numbers should be subscripts.) However there are isomers: CH3CH2CH2CH2CH2CH3, (CH 3 ) 2 CH(CH 2 ) 2 CH 3 CH 3 CH 2 CH(CH 3 )CH 2 CH 3 CH 3 CH(CH 3 )CH(CH 3 )CH 3 CH 3 C(CH 3 ) 2 CH 2 CH 3 Wikipedia shows them clearly.
Yes, C6H14 is a saturated hydrocarbon. Saturated hydrocarbons contain only single bonds between carbon atoms and are fully saturated with hydrogen atoms.