C6h14 + 13o2 ---> 7h2o + 6co2
The website keeps making correctinos to my capitalization of the elements, but this is the balanced equation.
When hexane (C6H14) reacts with oxygen gas (O2) in the presence of heat or a spark, combustion occurs producing carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for this reaction is: 2 C6H14 + 19 O2 -> 12 CO2 + 14 H2O.
The gram molecular mass of hexane is 86.18. Therefore, 25.0 g of hexane constitute 25.0/86.18 or 0.290 moles. Each mole of hexane contains six carbon atoms and therefore will produce six molecules of carbon dioxide by burning in an excess of oxygen. 6 X 0.290 = 1.74 moles of carbon dioxide. The gram molecular mass of carbon dioxide is 44.00. Therefore, the mass of carbon dioxide produced will be 1.74 X 44.00 or 76.6 grams of carbon dioxide, to the justified number of significant digits.
The equation for the dissolution of CO2 in water is: CO2 H2O H2CO3
The reactants are C and CO2. CO is formed when C and CO2 are reacted. So the product is CO.
The missing chemicals are 2LiOH + 2LiNO3 = H2O + CO2 + 4LiNO3.
When hexane (C6H14) reacts with oxygen gas (O2) in the presence of heat or a spark, combustion occurs producing carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for this reaction is: 2 C6H14 + 19 O2 -> 12 CO2 + 14 H2O.
To balance the equation C6H14 + O2 -> CO2 + H2O, start by balancing the carbon atoms. This requires putting a coefficient of 6 in front of CO2. Next, balance the hydrogen atoms by adding a coefficient of 7 in front of H2O. Finally, balance the oxygen atoms by adjusting the coefficient in front of O2, which in this case is 9.
2c6h14 + 15o2 -> 12co2 + 14h2o Stupid site again!! All letters are capitals.
Yes*. The empirical equation for this reaction is: 2C6H14 + 19O2 ---> 12CO2 + 14H2O. * n-Hexane, burned in an Iron III-catalyzed environment of pure oxygen gas, is oxidized completely. Intermediate products, such as peroxides are formed but the final products are carbon dioxide and water.
The gram molecular mass of hexane is 86.18. Therefore, 25.0 g of hexane constitute 25.0/86.18 or 0.290 moles. Each mole of hexane contains six carbon atoms and therefore will produce six molecules of carbon dioxide by burning in an excess of oxygen. 6 X 0.290 = 1.74 moles of carbon dioxide. The gram molecular mass of carbon dioxide is 44.00. Therefore, the mass of carbon dioxide produced will be 1.74 X 44.00 or 76.6 grams of carbon dioxide, to the justified number of significant digits.
The balanced equation is 2KHCO3(s) → K2CO3(s) + H2O(g) + CO2(g). The coefficient of carbon dioxide (CO2) in the balanced equation is 1.
To determine the number of moles of carbon dioxide produced when hexane is burned, we need to consider the balanced chemical equation for the combustion of hexane, which is C6H14 + 19/2 O2 -> 6 CO2 + 7 H2O. From the balanced equation, we can see that for every mole of hexane burned, 6 moles of carbon dioxide are produced. Therefore, if 84.4 moles of hexane is burned, 6 * 84.4 = 506.4 moles of carbon dioxide would be produced.
The equation for the dissolution of CO2 in water is: CO2 H2O H2CO3
The thermal decomposition has the following equation: CaCO3 --------CaO + CO2
To balance the equation for the reaction of C10H22 (decane) with C6H14 (hexane) and C2H4 (ethylene), you first need to identify the products, typically carbon dioxide (CO2) and water (H2O) if combustion is assumed. However, without specific conditions or products mentioned, it’s unclear how to balance this reaction properly. Please clarify the context or type of reaction for a precise balancing.
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.