2c6h14 + 15o2 -> 12co2 + 14h2o
Stupid site again!! All letters are capitals.
This equation, for complete combustion, is C8H16 + 12 O2 => 8 CO2 + 8 H2O. (The first formula in the equation is a molecular formula for ethylcyclohexane.)
The complete combustion of ethanol in oxygen proceeds according to the balanced equation C2H6O + 3 O2 -> 2 CO2 + 3 H2O.
This equation is C2H5OH + 3 O2 -> 2 CO2 + 3 H2O.
The reaction is:C6H12 + 9 O2 = 6 CO2 + 6 H2O
c12h26(i)--->c2h4(g)+______ Yuu shud work iht ouwt :)
The balanced decomposition chemical equation for hexane (C6H14) is: 2C6H14 → 6C + 7H2
The balanced equation for the combustion of magnesium is 2Mg + O2 -> 2MgO.
The complete combustion of hexane (C₆H₁₄) can be represented by the balanced equation: [ \text{C}6\text{H}{14} + 7\text{O}_2 \rightarrow 6\text{CO}_2 + 7\text{H}_2\text{O} ] In this reaction, for every molecule of hexane combusted, 7 molecules of water (H₂O) are formed.
Hexane + Oxygen -> Carbon Dioxide + Water - for full combustion Hexane + Oxygen -> Carbon + Carbon Monoxide + Water - for partial combustion
To determine the number of moles of carbon dioxide produced when hexane is burned, we need to consider the balanced chemical equation for the combustion of hexane, which is C6H14 + 19/2 O2 -> 6 CO2 + 7 H2O. From the balanced equation, we can see that for every mole of hexane burned, 6 moles of carbon dioxide are produced. Therefore, if 84.4 moles of hexane is burned, 6 * 84.4 = 506.4 moles of carbon dioxide would be produced.
Yes*. The empirical equation for this reaction is: 2C6H14 + 19O2 ---> 12CO2 + 14H2O. * n-Hexane, burned in an Iron III-catalyzed environment of pure oxygen gas, is oxidized completely. Intermediate products, such as peroxides are formed but the final products are carbon dioxide and water.
This equation, for complete combustion, is C8H16 + 12 O2 => 8 CO2 + 8 H2O. (The first formula in the equation is a molecular formula for ethylcyclohexane.)
The balanced equation for the combustion of polypropylene (C3H6)n is: C3H6 + 4.5O2 -> 3CO2 + 3H2O
The balanced equation for the combustion of heptane (C7H16) with oxygen (O2) is: C7H16 + 11O2 → 7CO2 + 8H2O
For complete combustion, the equation is C6H12 + 12 O2 = 6 CO2 + 6 H2O.
The complete combustion of ethanol in oxygen proceeds according to the balanced equation C2H6O + 3 O2 -> 2 CO2 + 3 H2O.
The balanced symbol equation for the combustion of coal is: C(s) + O2(g) -> CO2(g)