The complete combustion of hexane (C₆H₁₄) can be represented by the balanced equation:
[ \text{C}6\text{H}{14} + 7\text{O}_2 \rightarrow 6\text{CO}_2 + 7\text{H}_2\text{O} ]
In this reaction, for every molecule of hexane combusted, 7 molecules of water (H₂O) are formed.
C53+H778=undecane
helium is chemically inert and doesn't undergo combustion reaction
For complete combustion, the equation is C6H12 + 12 O2 = 6 CO2 + 6 H2O.
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
Coconut oil is a mixture, not a compound.
For every molecule of octane burned, 8 molecules of carbon dioxide are produced in a balanced reaction for the complete combustion of octane.
The complete combustion of ethanol in oxygen proceeds according to the balanced equation C2H6O + 3 O2 -> 2 CO2 + 3 H2O.
2C4H10 + 13O2 ==> 8CO2 + 10H2O complete combustion of isobutane
The balanced equation for the complete combustion of C18H36 is: C18H36 + 25.5 O2 → 18 CO2 + 18 H2O. This equation shows that every molecule of C18H36 reacts with 25.5 molecules of O2 to produce 18 molecules of CO2 and 18 molecules of H2O.
C53+H778=undecane
The balanced equation for the complete combustion of cyclooctane (C8H16) is: C8H16 + 12O2 -> 8CO2 + 8H2O
C3h5( c18h30)3)
2 Be + O2 = 2 BeO
helium is chemically inert and doesn't undergo combustion reaction
The reaction is:C6H12 + 9 O2 = 6 CO2 + 6 H2O
The balanced equation for the complete combustion of ethyne (C2H2) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O