helium is chemically inert and doesn't undergo combustion reaction
There is no word equation, except that helium will exist as liquid phase in liquid helium
Helium does not burn because it is an inert gas, meaning it does not undergo chemical reactions like combustion.
When a lighted splint is put into a glass jar of helium, the splint will immediately extinguish because helium is an inert gas that does not support combustion. The lack of oxygen in the helium prevents the splint from continuing to burn.
No, helium does not produce carbon dioxide. Helium is an inert gas and does not react chemically with other substances to produce carbon dioxide. Carbon dioxide is produced from the combustion of carbon-containing compounds.
The sun undergoes nuclear fusion, not chemical combustion. In its core, hydrogen atoms fuse together to form helium, releasing a tremendous amount of energy in the process. This energy is what powers the sun and makes it shine.
There is no word equation, except that helium will exist as liquid phase in liquid helium
No, helium is not required for combustion. Helium is an inert gas that is chemically non-reactive and does not support combustion. It is often used for filling balloons and airships due to its lightness and non-flammability.
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
Helium does not burn because it is an inert gas, meaning it does not undergo chemical reactions like combustion.
Hydrogen + intense heat and pressure --> Helium + energy release
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
6Li + 1n --> 7Li --> 3H + 4He Hyrogen-3 or tritium
No, helium does not readily undergo any chemical reactions.
Boron-10 (^10B) undergoing neutron capture forms boron-11 (^11B), followed by the emission of an alpha particle (helium-4 atom). The balanced nuclear equation would be: ^10B + n → ^11B + ^4He
When helium is burned, it produces a faint blue color. This is due to the electronic transitions that occur in the helium atoms during the combustion process.
When a lighted splint is put into a glass jar of helium, the splint will immediately extinguish because helium is an inert gas that does not support combustion. The lack of oxygen in the helium prevents the splint from continuing to burn.
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.