To balance the equation for the reaction of C10H22 (decane) with C6H14 (hexane) and C2H4 (ethylene), you first need to identify the products, typically carbon dioxide (CO2) and water (H2O) if combustion is assumed. However, without specific conditions or products mentioned, it’s unclear how to balance this reaction properly. Please clarify the context or type of reaction for a precise balancing.
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
Balanced equation C2H4 + 3O2 -> 2CO2 + 2H2O 125 grams ethylene (1 mole C2H4/28.052 grams)(2 mole CO2/1 mole C2H4)(44.01 grams/1 moleCO2) = 392 grams CO2 formed ==================
This monomer is ethene (or ethylene) - C2H4.
The final value for the enthalpy of reaction for the combustion of ethylene (C2H4) in your given reaction is -1410 kJ. This indicates that the reaction is exothermic, releasing 1410 kJ of energy as products (2 CO2 and 2 H2O) are formed from the reactants (C2H4 and 3 O2). Therefore, the enthalpy change, ΔH, for the complete combustion of ethylene is -1410 kJ.
450 moles of C2H4 contain 10.815,43 g carbon.
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
C2H4 + H2O --> C2H5OHReaction balanced at 1:1:1 mole of each compound, so you'll need 0.132 mol C2H4 and this is equal to:0.132 (mol C2H4) * 28 (g/mol C2H4) = 3.696 g C2H4 = 3.70 g C2H4
To find the mass of CO2 produced, first calculate the moles of C2H4 using its molar mass. Then, use the balanced equation to determine the moles of CO2 produced per mole of C2H4 reacted. Finally, convert moles of CO2 to grams using the molar mass of CO2.
The only way C2H4 can combust is in the presence of oxygen. All combustion reactions must contain a hydrocarbon and oxygen.
The balanced reaction for converting 1 mol of C2H4 to C2H4F2 using F2 gas is: C2H4 + 2 F2 -> C2H4F2 First, calculate the moles of C2H4 in 100g. Then, using the mole ratio from the balanced equation, determine how many moles of F2 are needed. Finally, convert the moles of F2 to liters using the ideal gas law (PV = nRT) at the given conditions.
The chemical equation for the reaction of C2H4 with H2O is C2H4 + H2O → C2H5OH (ethanol). This reaction results in the formation of ethanol by adding water across the carbon-carbon double bond in ethylene (C2H4).
Balanced equation C2H4 + 3O2 -> 2CO2 + 2H2O 125 grams ethylene (1 mole C2H4/28.052 grams)(2 mole CO2/1 mole C2H4)(44.01 grams/1 moleCO2) = 392 grams CO2 formed ==================
bg;iugi/lo[0'l
The chemical equation is not balanced. It should be balanced as follows: H2 + Cl2 → 2HCl
One Mole of C2H4 will containt 6.0221415×10^23 molecules of C2H4. Therefore 2.23 Moles of C2H4 will contain 1.39713683x10^24 molecules of C2H4. There are 4 Hydrogen atoms in C2H4, so 1.39713683x10^24 x 4 = 5.58854732X10^25 atoms of hydrogen.
c12h26(i)--->c2h4(g)+______ Yuu shud work iht ouwt :)
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2