As given ; NOTHING!!!!
If you mean
2K + 2H2O = 2KOH + H2
Note the use of capital letters and the '+/=' signs.
It is the potassium / water reaction, which is violent to the point of ignition or explosion.
The heat of the reaction, which has liberated hydrogen, then makes the hydrogen ignite and form water. (The explosion!!!!).
It is similar to but more violent than, the sodium/water reaction.
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and potassium (K) is: 2HCl + 2K -> 2KCl + H2.
2K(s) + 2H2O(l) = 2KOH(aq) + H2(g) The eq'n is balanced. The coefficients ( molar ratios) in order of the reation eq'n are 2:2:::2:1
The balanced equation for the reaction between potassium and water to form potassium hydroxide (KOH) and hydrogen gas (H2) is: 2K(s) + 2H2O(l) -> 2KOH(aq) + H2(g)
This is a chemical equation representing the reaction of potassium with water to form potassium hydroxide and hydrogen gas: 2K + 2H₂O → 2KOH + H₂. To balance it, simply ensure that the number of atoms of each element is the same on both sides of the equation. In this case, the equation is already balanced.
2K(s) + 2H2O(l) -> 2KOH(s) +H2(g) However, if potassium were dropped into water, there would be so much water that the KOH would not be solid but aqueous so it should read 2K(s) + 2H2O(l) -> 2KOH(aq) +H2(g)
2K + H2O ----> K2O + H2
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and potassium (K) is: 2HCl + 2K -> 2KCl + H2.
2K(s) + 2H2O(l) = 2KOH(aq) + H2(g) The eq'n is balanced. The coefficients ( molar ratios) in order of the reation eq'n are 2:2:::2:1
The balanced equation for the reaction between potassium and water to form potassium hydroxide (KOH) and hydrogen gas (H2) is: 2K(s) + 2H2O(l) -> 2KOH(aq) + H2(g)
2k + 2h2o --> 2 koh + h2 (Actual chemical symbols are in capital letters, we are having a technical problem.)
This is a chemical equation representing the reaction of potassium with water to form potassium hydroxide and hydrogen gas: 2K + 2H₂O → 2KOH + H₂. To balance it, simply ensure that the number of atoms of each element is the same on both sides of the equation. In this case, the equation is already balanced.
2K+ + 4H+ + 2O2- = 2K++ 2OH- + H2 Sodium is a reducing metal.
2K(s) + 2H2O(l) -> 2KOH(s) +H2(g) However, if potassium were dropped into water, there would be so much water that the KOH would not be solid but aqueous so it should read 2K(s) + 2H2O(l) -> 2KOH(aq) +H2(g)
if you mean what the reaction is then... 2K + 2H2O --> H2 + 2KOH The products are hydrogen gas and potassium hydroxide.
Balanced :2 K + 2 H2O ----> 2 KOH + H2
1 (fully) and 4 (only partial) are decomposition reactions.
The balanced chemical equation for the reaction between potassium (K) and sulfuric acid (H2SO4) to form potassium sulfate (K2SO4) and hydrogen gas (H2) is: 2K + H2SO4 -> K2SO4 + H2