Na2Cr2O7 (the formula is not Na2CrO7) is sodium dichromate.
Na2CrO4 is sodium chromate.
Sodium chromate is the name of the compound Na2CrO4.
It is soluble but does take a little effort to get it into solution.
The oxidation number of Na in Na2CrO4 is +1 and the oxidation number of O in Na2CrO4 is -2. To find the oxidation number of Cr, we let x be the oxidation number: 2(+1) + x + 4(-2) = 0 x = +6 Therefore, the oxidation number of Cr in Na2CrO4 is +6.
The chemical reaction is:Na2Cr2O7 + 2 NaOH = 2 Na2CrO4 + H2O
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
Sodium chromate is the name of the compound Na2CrO4.
The chemical formula of sodium chromate is Na2CrO4.
It is soluble but does take a little effort to get it into solution.
The oxidation number of Na in Na2CrO4 is +1 and the oxidation number of O in Na2CrO4 is -2. To find the oxidation number of Cr, we let x be the oxidation number: 2(+1) + x + 4(-2) = 0 x = +6 Therefore, the oxidation number of Cr in Na2CrO4 is +6.
The chemical reaction is:Na2Cr2O7 + 2 NaOH = 2 Na2CrO4 + H2O
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
Na2CrO4
The chemical formula for sodium dichromate is Na2Cr2O7.
If 2 moles of Na2CrO4 react completely, they will form the same number of moles of NaCl. This is because the mole ratio between Na2CrO4 and NaCl is 1:2. Therefore, 2 moles of Na2CrO4 will form 2 moles of NaCl.
Oh, dude, let's break it down. So, first off, you gotta calculate the molar mass of Na2CrO4, which is around 205.99 g/mol. Then, you divide the given mass by the molar mass to find the moles. In this case, 74.3 g / 205.99 g/mol gives you approximately 0.36 moles of Na2CrO4. So, there you have it, like, around 0.36 moles of that stuff in 74.3 grams.
To find the number of moles of Na2CrO4 in 74.3 grams, you need to divide the given mass by the molar mass of Na2CrO4. The molar mass of Na2CrO4 is calculated by adding the atomic masses of all the elements: 2(Na) + Cr + 4(O). Then divide 74.3 grams by the molar mass of Na2CrO4 to get the number of moles.
The balanced equation for the reaction between barium chloride (BaCl2) and sodium chromate (Na2CrO4) is: BaCl2 + Na2CrO4 -> BaCrO4 + 2NaCl