Sodium (Na) plus sulfur (S) creates sodium sulfide (Na2S). The reason is that Na gives up it's valence electron and S takes it. It takes 2 sodiums because S need TWO electrons to complete the octet. This forms the ionic compound sodium sulfide.
The chemical formula of sodium sulfide is Na2S.
Not sure what L(s) is supposed to be, but regardless, the oxidation state of Na changes from 1+ in NaOH to zero in Na(s).
No, it should be:2 Na(s) + 2HCl(g) --> H2(g) + 2 NaCl(s)By the way: sodium at normal conditions is a solid metal (s), not gaseous (g)
2HCl + Na(2)S-----> H(2)S + 2NaCl
4,1,2
Net Ionic: Cd^+2+(aq) + S^2-(aq) ==> CdS(s)The Na^+ and Cl^- are spectator ions.
seriously
Not sure what L(s) is supposed to be, but regardless, the oxidation state of Na changes from 1+ in NaOH to zero in Na(s).
no 2Na (s) + MgF2 ? 2NaF (s) + Mg (s) is balanced apex
Lithium atom become the cation Li+.
it goes from +1 to 0
No, it should be:2 Na(s) + 2HCl(g) --> H2(g) + 2 NaCl(s)By the way: sodium at normal conditions is a solid metal (s), not gaseous (g)
If you mean a reaction of AgNO3 + Na(s) ==> NaNO3 + Ag(s), there would be ONE electron transferred.Ag^+ + 1e- ==> Ag(s) Reduction reaction Na(s) ==> Na^+ + 1e- Oxidation reaction
Na+ and Cl- are spectator ions.
2HCl + Na(2)S-----> H(2)S + 2NaCl
4,1,2
Na+is bigger
Lithium atom become the cation Li+.