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Supply the missing products in the following chemical equation KClaq NaOHaq?
The missing products in the given chemical equation KClaq + NaOHaq are NaClaq (sodium chloride) and KOHaq (potassium hydroxide).
What are the two products HClaq NaOHaq?
=> NaClaq + H2O + heat
What is the net ionic equation for MgNO32aq plus NaOHaq?
It happens to be because of the law of phisics. In my class in collage it means table salt.
Does Na H2O NAOHaq H2g obey the law of conservation of matter?
Yes, the equation obeys the law of conservation of matter. The number of atoms for each element is the same on both sides of the equation, indicating that no atoms are created or destroyed during the reaction.
The neutralization of h2so4aq using naohaq is represented by the following equation 2naohaq h2so4aq -- na2so4aq 2h2ol if 30.40 ml of 0.500 m naohaq is neutralized by 22.02 ml of?
To find the molarity of the sulfuric acid (H2SO4), we first calculate the number of moles of NaOH used: 30.40 mL * 0.500 mol/L = 15.20 mmol NaOH. Since the mole ratio between NaOH and H2SO4 is 2:1, 15.20 mmol of NaOH would neutralize 7.60 mmol of H2SO4. Now we can find the molarity of H2SO4 using its volume: 7.60 mmol / 22.02 mL = 0.345 M H2SO4.
What is the complete ionic equation for NaOHaq plus HCIaq equals H2OI plus NaCIaq?
Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
What is the complete ionic equation for naohaq hciaqh2oi naciaq?
The complete ionic equation is: Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) + H2O(l) -> Na+(aq) + Cl-(aq) + H2O(l) In this reaction, the NaOH dissociates into Na+ and OH- ions, and HCl dissociates into H+ and Cl- ions. The H+ ion reacts with the OH- ion to form water, which results in the net ionic equation shown above.
When NaOHaq reacts completely with HCLaq and the resulting solution is evaporated to dryness the solid remaining is?
Sodium chloride (NaCl) would be left behind after evaporating the solution to dryness. This is because when sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl), it forms sodium chloride and water. Evaporating the water leaves behind solid sodium chloride.
In which laboratory process could a student use 0.10 M NaOHaq to determine the concentration of an aqueous solution of HBr?
A student could use the 0.10 M NaOH solution in a titration experiment to determine the concentration of an aqueous solution of HBr by slowly adding the NaOH to the HBr solution until the equivalence point is reached. By monitoring the volume of NaOH required to neutralize the HBr solution, the student can calculate the concentration of the HBr solution using the equation C1V1 = C2V2, where C1 and V1 are the concentration and volume of NaOH and C2 and V2 are the concentration and volume of the HBr solution.
How would you convert 2 chloropropane to propene?
when 2 chlori propane is reacted in presence of ethanolic koH it form propene .
