When zinc (Zn) is combined with sodium hydroxide (NaOH), the reaction produces sodium zincate and hydrogen gas. The chemical equation is: Zn + 2NaOH -> Na2ZnO2 + H2.
The products in the reaction of Zn(NO3)2 with 2 NaOH are Zn(OH)2(s) and 2 NaNO3 . There are no 'elements' involved
NaOH can react with Zn to form zincate ions (Zn(OH)4) and hydrogen gas. This reaction can corrode or dissolve the zinc surface, especially in alkaline conditions.
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.
intially: Zn2+ + 2OH- -->Zn(OH)2 excess hydroxide: Zn(OH)2 + 2OH- --> [Zn(OH)4]2- It is true that excess hydroxide reacts further, but the reaction is as under: Zn(OH)2 +2(OH)- ----> (ZnO2) 2- +2H2O or ZnSO4 + 4NaOH ------> 2Na2ZnO2 +2H2O, the white precipitate of zinc hydroxide dissolves with excess hydroxide and forms a soluble complex called sodium zincate. The solution becomes clear. No ppt.
ZnCl2 + NaOH --> NaCl2 + ZnOH Zn2+ + Cl- + Na+ +OH- --> Na+ + Cl- + ZnOH Zn+ + OH- ---> ZnOH(s)
The products in the reaction of Zn(NO3)2 with 2 NaOH are Zn(OH)2(s) and 2 NaNO3 . There are no 'elements' involved
NaOH can react with Zn to form zincate ions (Zn(OH)4) and hydrogen gas. This reaction can corrode or dissolve the zinc surface, especially in alkaline conditions.
There's two possible reactions Zink with solid NaOH gives double salt Zn + 2NaOH --t--> Na2ZnO2 + H2 And I Think you need the other one: Zink with NaOH(aq) gives the complex salt: Zn + 2NaOH + 2H2O --> Na2[Zn(OH)4] + H2
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.
Zn + CuBr2 = Cu + ZnBr2
intially: Zn2+ + 2OH- -->Zn(OH)2 excess hydroxide: Zn(OH)2 + 2OH- --> [Zn(OH)4]2- It is true that excess hydroxide reacts further, but the reaction is as under: Zn(OH)2 +2(OH)- ----> (ZnO2) 2- +2H2O or ZnSO4 + 4NaOH ------> 2Na2ZnO2 +2H2O, the white precipitate of zinc hydroxide dissolves with excess hydroxide and forms a soluble complex called sodium zincate. The solution becomes clear. No ppt.
Aluminium hydroxide = Al(OH)3 , and Zinc hydroxide = Zn(OH)2 , is redissolved in excess Sodium hydroxide = NaOH (in water solution) : Al(OH)3 + NaOH + H2O ----> NaAl(OH)4 Zn(OH)2 + NaOH + H2O ----> Na2Zn(OH)4
Simple methods:- reaction of Zn with HCl- reaction of Al with NaOH
zinc nitrate + sodium hydroxide yields sodium nitrate and zinc hydroxide( white precipitate)
Zn + CuSO4 --> ZnSO4 + Cu
ZnCl2 + NaOH --> NaCl2 + ZnOH Zn2+ + Cl- + Na+ +OH- --> Na+ + Cl- + ZnOH Zn+ + OH- ---> ZnOH(s)
Zn + 2HCl >> ZnCl2 + H2