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The first electron ring is filled with 2 electrons. The next is filled with 8. So an element with the first two rings filled and 7 electrons in the third would have a total of 17 electrons.

(NOTE: The term shell isn't exactly right, since in nuclear physics, each "shell" only holds 2 electrons, and they are all filled in a certain order based on energy levels. This is more complex than the simple high school chemistry model of rings, though, and your question seems to be asking about the rings due to the "7 on the third energy level" part.)

For it to be neutral, it will have the same number of protons as electrons, 17.

The first 2 are the top row, Hydrogen and Helium.

The next 8 are the second row.

So if we go 7 across (left to right) on the third row, we get to CL.

The element you're asking about is Chlorine.

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Q: What is a neutral atom that has its first two shells filled has 7 electrons on the third energy level and has no other electrons?
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