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AgI and CuBr2 are both soluble in water. AgI is slightly soluble and CuBr2 is highly soluble in water, forming a greenish solution due to the presence of copper ions.
The balanced equation for the reaction between zinc (Zn) and copper (II) bromide (CuBr2) is: Zn + CuBr2 → ZnBr2 + Cu
The classical method for preparing CuBr2 involves reacting copper oxide or carbonate with hydrobromic acid. This reaction forms copper bromide and water as products. The balanced chemical equation for this reaction is CuO + 2HBr -> CuBr2 + H2O.
The formula for copper (II) bromide is CuBr2. It consists of one copper (Cu) atom bonded to two bromine (Br) atoms.
No, the chemical formula CuBr2 indicates one atom of copper bonding with two atoms of bromine. This means that the molar mass of CuBr2 is not equal to the sum of the molar masses of copper and bromine individually.
Zn + CuBr2 = Cu + ZnBr2
The percent composition for CuBr2 is: Cu= 28.45% Br= 71.55%
AgI and CuBr2 are both soluble in water. AgI is slightly soluble and CuBr2 is highly soluble in water, forming a greenish solution due to the presence of copper ions.
The balanced equation for the reaction between zinc (Zn) and copper (II) bromide (CuBr2) is: Zn + CuBr2 → ZnBr2 + Cu
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The classical method for preparing CuBr2 involves reacting copper oxide or carbonate with hydrobromic acid. This reaction forms copper bromide and water as products. The balanced chemical equation for this reaction is CuO + 2HBr -> CuBr2 + H2O.
Formula: CuBr2
The formula for copper (II) bromide is CuBr2. It consists of one copper (Cu) atom bonded to two bromine (Br) atoms.
There are two atoms of Bromine (Br) and one atom of Copper (Cu) in this compound. Thus, there are two elements, but three atoms.
Cu+2 Br-1
No, the chemical formula CuBr2 indicates one atom of copper bonding with two atoms of bromine. This means that the molar mass of CuBr2 is not equal to the sum of the molar masses of copper and bromine individually.
Na3PO4+CuBr2=Cu3(PO4)2+NaBr PO4 has a charge of -3 and Cu (in this equation as shown by CuBr2) has a charge of +2, when they combine you switch the chareges and add them on as subscripts to each other. Na and Br have the opposite charges, -1 and +1, so you don't have to add them to the equation.