Na3PO4+CuBr2=Cu3(PO4)2+NaBr
PO4 has a charge of -3 and Cu (in this equation as shown by CuBr2) has a charge of +2, when they combine you switch the chareges and add them on as subscripts to each other. Na and Br have the opposite charges, -1 and +1, so you don't have to add them to the equation.
Na3PO4
So you have 0.25 molar Na3PO4. But for every one molecule of Sodium phosphate, you have 3 molecules of sodium. Therefore you have 0.25*3 or 0.75 molar sodium.
It is a single displacement reaction. No balancing is needed in the resulting equation. Zn + CuBr2 ----> ZnBr2 + Cu
This formula is Na3PO4.
H3PO4 + 3NaOH --------> Na3PO4 + 3H2O
Na3PO4
So you have 0.25 molar Na3PO4. But for every one molecule of Sodium phosphate, you have 3 molecules of sodium. Therefore you have 0.25*3 or 0.75 molar sodium.
It is a single displacement reaction. No balancing is needed in the resulting equation. Zn + CuBr2 ----> ZnBr2 + Cu
This formula is Na3PO4.
H3PO4 + 3NaOH --------> Na3PO4 + 3H2O
Na3PO4 and CuSO4
3, 2, 2, 1
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
The chemical reaction is:H3PO4 + 3 NaOH + Na3PO4 + 3 H2O
Na3(PO4)3 + NiCl2 => ...
The reaction is:3 MgSO4 + 2 Na3PO4 = Mg3(PO4)2 + 3 Na2SO4
No. The mole of solution is equal to mole of solute plus mole of solvent (solVENT !, not solution)