Na3PO4+CuBr2=Cu3(PO4)2+NaBr
PO4 has a charge of -3 and Cu (in this equation as shown by CuBr2) has a charge of +2, when they combine you switch the chareges and add them on as subscripts to each other. Na and Br have the opposite charges, -1 and +1, so you don't have to add them to the equation.
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.
Na3PO4
The balanced equation for the reaction between zinc (Zn) and copper (II) bromide (CuBr2) is: Zn + CuBr2 → ZnBr2 + Cu
The compound formed by Na+ and PO43- ions is sodium phosphate, which has the chemical formula Na3PO4.
The concentration of Na+ in Na3PO4 is 0.090 M. This is because for every 1 mole of Na3PO4, there are 3 moles of Na+ ions. So in a 0.030 M solution of Na3PO4, the concentration of Na+ is 3 times that, which is 0.090 M.
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.
Na3PO4
The balanced equation for the reaction between zinc (Zn) and copper (II) bromide (CuBr2) is: Zn + CuBr2 → ZnBr2 + Cu
The compound formed by Na+ and PO43- ions is sodium phosphate, which has the chemical formula Na3PO4.
Na3PO4 and CuSO4
The concentration of Na+ in Na3PO4 is 0.090 M. This is because for every 1 mole of Na3PO4, there are 3 moles of Na+ ions. So in a 0.030 M solution of Na3PO4, the concentration of Na+ is 3 times that, which is 0.090 M.
3, 2, 2, 1
3Ca(NO3)2 + 2Na3PO3 >> Ca3(PO3)2 + 6NaNO3
Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.750 Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 =================== 0.28125 moles Na2SO4 (142.05 grams/1 mole Na2SO4) = 39.95 grams Na2SO4 needed ---------------------------------------you do significant figures!
The chemical reaction is:H3PO4 + 3 NaOH + Na3PO4 + 3 H2O
The reaction is:3 MgSO4 + 2 Na3PO4 = Mg3(PO4)2 + 3 Na2SO4
Yes, you need to put the PO4 in parentheses and add a 3 subscript to indicate that there are 3 phosphate ions in the compound. The product of Na3PO4 + NiCl2 would be Ni3(PO4)2 + 6NaCl.