The equilibrium constant expression for the reaction you provided would be ( K_a = \frac{[H^+][H_2BO_3^-]}{[H_3BO_3]} ). However, the specific value of ( K_a ) for this reaction would depend on the concentrations of the species involved in the particular experimental conditions.
Ka= [H+] [H2BO3-] / [h3BO3] (Apex)
ka=[H+][CN-]/[HCN]
Ka= [h+][HCO3-]/[H2CO3]
The Ka for the dissociation of HNO2 is 4.5 x 10^-4. This value represents the equilibrium constant for the reaction of HNO2 dissociating into H+ and NO2-.
not sure
HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
3.4 * 10^-8
The acid dissociation constant (Ka) for carbonic acid (H₂CO₃) dissociating into hydrogen ions (H⁺) and bicarbonate ions (HCO₃⁻) is a measure of the strength of the acid in solution. The dissociation reaction can be represented as: H₂CO₃ (aq) ⇌ H⁺ (aq) + HCO₃⁻ (aq). The value of Ka for this process is approximately 4.3 x 10⁻⁷ at 25°C, indicating that H₂CO₃ is a weak acid.
ka=[H+][NO2_]/[HNO2]
Ka= [H+] [H2BO3-] / [h3BO3] (Apex)
ka=[H+][CN-]/[HCN]
6.6 x 10-9
Ka= [h+][HCO3-]/[H2CO3]
The acid dissociation constant (Ka) for the dissociation of nitrous acid (HNO2) into hydrogen ions (H⁺) and nitrite ions (NO2⁻) can be expressed with the equation: [ K_a = \frac{[H^+][NO_2^-]}{[HNO_2]} ] This equilibrium constant quantifies the strength of HNO2 as an acid; a larger Ka value indicates a stronger acid, meaning it dissociates more completely in solution. For HNO2, the Ka is approximately 4.5 × 10⁻⁴ at 25°C, indicating it is a weak acid.
The Ka for the dissociation of HNO2 is 4.5 x 10^-4. This value represents the equilibrium constant for the reaction of HNO2 dissociating into H+ and NO2-.
not sure
Ka= [H+][NO2-] [HNO2]