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What is the mass of 3 moles of barium?
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
How many grams of Ba(CH3COO)2 are there in 237 grams of an aqueous solution that is 25.7 by weight Ba(CH3COO)2.?
To find the grams of Ba(CH3COO)2 in the solution, calculate the mass of Ba(CH3COO)2 using the percentage data (25.7%) provided. Mass of Ba(CH3COO)2 in 237 g solution = 237 g x 25.7% = 60.99 g Therefore, there are 60.99 grams of Ba(CH3COO)2 in the solution.
What is the mass of 0.75 mole of so2?
The molar mass of SO2 (sulfur dioxide) is approximately 64.06 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles (0.75) by the molar mass (64.06 g/mol) to get the mass of 0.75 moles of SO2, which is 48.045 grams.
How many moles of BaOH2 are in 2400 grams of BaOH 2?
To find the number of moles in 2400 grams of Ba(OH)2, divide the given mass by the molar mass of Ba(OH)2. The molar mass of Ba(OH)2 is 171.34 g/mol. So, 2400 g / 171.34 g/mol = 14.00 mol of Ba(OH)2.
How many grams of NaOH are in 1.25 mol NaOH?
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2
What is the mass of 3 moles of barium?
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
How many moles of barium are present in a sample having a mass of 22.3 grams?
To determine the number of moles present, we first need to find the molar mass of barium (Ba), which is approximately 137.33 g/mol. Next, we use the formula n = m/M, where n is the number of moles, m is the mass of the sample (22.3 grams), and M is the molar mass (137.33 g/mol). By substituting these values, we find that there are approximately 0.162 moles of barium in the sample.
How many grams of Ba(CH3COO)2 are there in 237 grams of an aqueous solution that is 25.7 by weight Ba(CH3COO)2.?
To find the grams of Ba(CH3COO)2 in the solution, calculate the mass of Ba(CH3COO)2 using the percentage data (25.7%) provided. Mass of Ba(CH3COO)2 in 237 g solution = 237 g x 25.7% = 60.99 g Therefore, there are 60.99 grams of Ba(CH3COO)2 in the solution.
What is the mass of one molecule of barium BaSiF6?
Barium siliconhexafluoride. 279.39 grams BaSiF6 = 1 mole of BaSiF6/6.022 X 10^23 = 1.66 X 10^-24, which is the mole ratio of one molecule of BaSiF6. So, ... (279.39 grams) * (1.66 X 10^-24) = 4.64 X 10^-22 grams in one molecule of BaSiF6
What is the mass of one mole of barium nitrate?
First, we need to find the formula for barium nitrate. Barium's charge is 2+, and nitrate is a 1-. If you criss-cross charges, the resulting formula is Ba(NO3)2. Now that we have the formula, we need to find the atomic mass. Barium has an atomic mass of 137. Nitrate is composed of nitrogen (14.01g) and oxygen (16.00*3 = 48). The atomic mass of nitrate is 62.01. Since there are two NO3 molecules, we multiply by 2 to get 124.02. Finally, we add the barium for a grand total of 261.02. Finally, we set-up our conversion ratios: 432 g Ba(NO3)2/1 * 1 mol/261.02g = 1.66 mols
What is the mass of 0.75 mole of so2?
The molar mass of SO2 (sulfur dioxide) is approximately 64.06 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles (0.75) by the molar mass (64.06 g/mol) to get the mass of 0.75 moles of SO2, which is 48.045 grams.
How many moles of BaOH2 are in 2400 grams of BaOH 2?
To find the number of moles in 2400 grams of Ba(OH)2, divide the given mass by the molar mass of Ba(OH)2. The molar mass of Ba(OH)2 is 171.34 g/mol. So, 2400 g / 171.34 g/mol = 14.00 mol of Ba(OH)2.
How many grams of NaOH are in 1.25 mol NaOH?
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2
When a .269 g sample of barium compound was treated with excess H2SO4 .0891 g of BaSO4 formed What is the percentage of barium in the compound?
The molar mass of BaSO4 is 233.4 g/mol. Therefore, 0.0891 g of BaSO4 corresponds to 0.000382 moles of BaSO4. Since BaSO4 contains 1 mole of Ba for every 1 mole of BaSO4, the original sample contained 0.000382 moles of Ba. The percentage of barium in the compound is calculated as (mass of Ba / total mass of the compound) * 100, which equals approximately 0.143%.
How many moles of Ba(OH)2 are in 2400 grams of Ba(OH)2?
To find the number of moles, divide the given mass of Ba(OH)2 (2400g) by its molar mass. The molar mass of Ba(OH)2 is calculated as 137.33 (Ba) + 216.00 (O) + 21.01 (H), resulting in approximately 171.35 g/mol. Dividing 2400g by 171.35 g/mol gives approximately 14.01 moles of Ba(OH)2.
What is the percentage of Ba compound when 0.269 g sample of Ba compound was treated with excess H2SO4 0.0891 g of BaSo4 was formed?
The molar mass of BaSO4 is 233.4 g/mol. From the given data, the number of moles of BaSO4 formed can be calculated as 0.0891 g / 233.4 g/mol = 3.82 x 10^-4 moles. Since 1 mole of BaSO4 contains 1 mole of Ba, the number of moles of Ba in the sample is also 3.82 x 10^-4. The percentage of Ba in the original sample is then (3.82 x 10^-4 moles / molar mass of Ba) x 100%.
How many atoms in one mole of barium?
One mole of anything is approximately 6.022 x 1023 units. So, one mole of Ba would be 6.022 x 1023 atoms. One mole of H would be 6.022 x 1023. And so forth...
