What is number of the H atoms in 6.37ng of C6H5NO2?

Answer 1

The number of H atoms in 6.37ng of C6H5NO2 are 12 in total.

Answer 2

The molar mass of C6H5NO2 is: C: 6 atoms x 12 g/mol = 72 g/mol H: 5 atoms x 1 g/mol = 5 g/mol N: 1 atom x 14 g/mol = 14 g/mol O: 2 atoms x 16 g/mol = 32 g/mol Total = 123 g/mol

6.37 ng is equivalent to 6.37 x 10^-9 g.

Calculate the number of moles using the molar mass: 6.37 x 10^-9 g / 123 g/mol ≈ 5.17 x 10^-11 mol

There are 5 H atoms in one molecule of C6H5NO2, so in 5.17 x 10^-11 mol, there are approximately 5.17 x 10^-11 mol x 5 = 2.59 x 10^-10 moles of H atoms.