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+6 for Cr
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What is the oxidation number of chromium in K2Cr2O7?
The oxidation number of chromium in K2Cr2O7 is +6. Each potassium ion has an oxidation state of +1, and each oxygen atom has an oxidation state of -2. By setting up an equation based on the overall charge of the compound, it can be determined that chromium has an oxidation state of +6.
What is the oxidation number of Cr in K2Cr2O7 formula?
The oxidation number of Cr in K2Cr2O7 is +6. This can be determined by assigning the oxidation number of +1 to each K atom, the oxidation number of -2 to each O atom, and applying the rule that the sum of oxidation numbers in a neutral compound is zero.
What is the oxidation number of one chromium atom in potassium dichromate?
The oxidation number of one chromium atom in potassium dichromate (K2Cr2O7) is +6. This is because each oxygen atom has an oxidation number of -2 and each potassium atom has an oxidation number of +1, so the overall charge of the compound is zero, making the oxidation number of chromium +6 to balance it out.
What is the oxidation number of Cr is acidified potassium dichromate?
The oxidation number of Cr in acidified potassium dichromate (K2Cr2O7) is +6. This is because each oxygen atom has an oxidation number of -2, and the overall charge of the dichromate ion is -2.
Why H2SO4 is added in K2Cr2O7 during oxidation of alcohol?
H2SO4 is added in the oxidation of alcohols with K2Cr2O7 as a catalyst to provide acidic conditions, which facilitate the oxidation reaction. The sulfuric acid protonates the alcohol to form an oxonium ion, which is more easily oxidized by the chromate ion in K2Cr2O7. This helps to increase the efficiency and speed of the oxidation process.
What is the oxidation number of chromium in K2Cr2O7?
The oxidation number of chromium in K2Cr2O7 is +6. Each potassium ion has an oxidation state of +1, and each oxygen atom has an oxidation state of -2. By setting up an equation based on the overall charge of the compound, it can be determined that chromium has an oxidation state of +6.
What is the oxidation number of Cr in K2Cr2O7 formula?
The oxidation number of Cr in K2Cr2O7 is +6. This can be determined by assigning the oxidation number of +1 to each K atom, the oxidation number of -2 to each O atom, and applying the rule that the sum of oxidation numbers in a neutral compound is zero.
What is the oxidation number of Cr is acidified potassium dichromate?
The oxidation number of Cr in acidified potassium dichromate (K2Cr2O7) is +6. This is because each oxygen atom has an oxidation number of -2, and the overall charge of the dichromate ion is -2.
What is the oxidation number of one chromium atom in potassium dichromate?
The oxidation number of one chromium atom in potassium dichromate (K2Cr2O7) is +6. This is because each oxygen atom has an oxidation number of -2 and each potassium atom has an oxidation number of +1, so the overall charge of the compound is zero, making the oxidation number of chromium +6 to balance it out.
Why H2SO4 is added in K2Cr2O7 during oxidation of alcohol?
H2SO4 is added in the oxidation of alcohols with K2Cr2O7 as a catalyst to provide acidic conditions, which facilitate the oxidation reaction. The sulfuric acid protonates the alcohol to form an oxonium ion, which is more easily oxidized by the chromate ion in K2Cr2O7. This helps to increase the efficiency and speed of the oxidation process.
What is the oxidation equation of the reaction of propanal with potassium dichromate?
The oxidation of propanal (CH3CH2CHO) by potassium dichromate (K2Cr2O7) in acidic conditions produces propanoic acid (CH3CH2COOH). The oxidation equation is: CH3CH2CHO + K2Cr2O7 + H2SO4 → CH3CH2COOH + Cr2(SO4)3 + K2SO4 + H2O.
What is the oxidation number for 0 in k2cr207?
In K2Cr2O7, the oxidation number of oxygen is typically -2. Since there are two oxygen atoms in the dichromate ion (Cr2O7)^2-, the total oxidation number contribution from oxygen is -14. To balance this, the oxidation number of Cr is +6. Therefore, the oxidation number of O in this compound is -2.
What is the oxidation number of chromium in potassium dichromate?
The oxidation number of chromium in potassium dichromate is +6. Each oxygen has an oxidation number of -2, and since the compound is neutral, the oxidation number of potassium is +1. This means the two chromium atoms in potassium dichromate each have an oxidation number of +6 to balance the charges.
What is the equivalent weight of K2Cr2O7 fully explanation?
The equivalent weight of K2Cr2O7 is determined by the number of moles of electrons transferred in a redox reaction per mole of the substance. For K2Cr2O7, the equivalent weight is calculated using the total change in oxidation state divided by the number of moles of K2Cr2O7 involved in the reaction. This value is used to quantify the amount of K2Cr2O7 needed to gain or lose an equivalent amount of electrons in a redox reaction.
What is the oxidation state of chromium in the compound K2Cr2O7?
The oxidation state of chromium in K2Cr2O7 is +6. This can be determined by assigning oxidation states to the other elements in the compound (K = +1, O = -2) and using the overall charge of the compound (zero) to calculate the oxidation state of chromium.
Oxidation number of Cr in K2Cr2O7?
Potassium is the metal here and it has an Oxidation number of +1 in every compound because all Alkali Earth metals have an Oxidation Number of +1. (The other elements: Oxygen -2 and Chromium (Cr) +6)
How many potassium atoms are there in a sample of K2Cr2O7 having a mass of 24.43 g?
To find the number of potassium atoms in a sample of K2Cr2O7, you first need to calculate the number of moles of K2Cr2O7 using its molar mass. Then, you can determine the number of moles of potassium atoms since there are 2 potassium atoms in each molecule of K2Cr2O7. Finally, use Avogadro's number (6.022 x 10^23) to convert the number of moles of potassium atoms to the actual number of atoms.
