0
4
SnO32-
calculation can be done to find the unknown oxidation state of tin
let; X=Sn
because of the overall charge is -2, the equation must equal to -2
X + 3(oxidation no of oxygen)=-2
X + 3(-2)=-2
X + (-6) = -2
X = +4
So, the oxidation no for tin in SnO32- is +4
this calculation can be rechecked to confirm the answer by substituting +4 back in the equation;
(+4) + (-6) = -2
and here we go
the answer was correct
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∙ 14y ago
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