+5
The oxidation number of Mn in KMnO4 is +7. This can be determined by assigning the known oxidation numbers of potassium (+1) and oxygen (-2) and solving for the unknown oxidation number of manganese.
First O has an oxidation number of -2; K will an oxidation number of +1 as it is an alkali metal. Therfore the Mn is +6. note that while the manganate ion exists, the question may relate to the permanganate ion MnO4-, so KMnO4, where Mn has oxidation number of +7
The oxidation number for H is +1, and the oxidation number for O is -1.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
In LiH, the oxidation number of Li is +1 and the oxidation number of H is -1. This is because lithium typically has a +1 oxidation state and hydrogen typically has a -1 oxidation state in ionic compounds.
The oxidation number of Mn in KMnO4 is +7. This can be determined by assigning the known oxidation numbers of potassium (+1) and oxygen (-2) and solving for the unknown oxidation number of manganese.
First O has an oxidation number of -2; K will an oxidation number of +1 as it is an alkali metal. Therfore the Mn is +6. note that while the manganate ion exists, the question may relate to the permanganate ion MnO4-, so KMnO4, where Mn has oxidation number of +7
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number for H is +1, and the oxidation number for O is -1.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
In LiH, the oxidation number of Li is +1 and the oxidation number of H is -1. This is because lithium typically has a +1 oxidation state and hydrogen typically has a -1 oxidation state in ionic compounds.
The oxidation number of the ion F1- is -1.
The oxidation number for iodine in IF is -1. Fluorine always has an oxidation number of -1 in compounds.
Pottasium has +1 oxidation number.Iodine has -1 oxidation number.
This number is -1.
The oxidation number of Li in LiBr is +1, and the oxidation number of Br is -1.
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.