The oxidation number of the ion F1- is -1.
oxidation number of I is -1. oxidation number of F is +1.
The oxidation number of F, or Fluorine, is F-1. Since it is in the seventh group on the periodic table, it has seven valence electrons. It needs to get eight valence electrons to be stable, so it will gain one electron.
+1 for K -1 for F
Fluorine (F) has a oxidation number of -1 in F4 there are four -1 with a total of -4. Now to have a a balance of 0 positive or negative charges -4+?=0. Sulfur has to have +4 charge to balance the compund to zero.
The compound has no charge. This means that the positive oxidation numbers must equal the negative oxidation numbers. 'H' always has an oxidation number of +1. There are three of these atoms in the compound giving +3. To cancel out this positive number, the 'B' must equal -3.
oxidation number of I is -1. oxidation number of F is +1.
In compounds fluorine, F, has an oxidation number of -1.
The oxidation number of F, or Fluorine, is F-1. Since it is in the seventh group on the periodic table, it has seven valence electrons. It needs to get eight valence electrons to be stable, so it will gain one electron.
+1 for K -1 for F
Fluorine (F) has a oxidation number of -1 in F4 there are four -1 with a total of -4. Now to have a a balance of 0 positive or negative charges -4+?=0. Sulfur has to have +4 charge to balance the compund to zero.
The compound has no charge. This means that the positive oxidation numbers must equal the negative oxidation numbers. 'H' always has an oxidation number of +1. There are three of these atoms in the compound giving +3. To cancel out this positive number, the 'B' must equal -3.
A molecule hasn't an oxidation number.
Cu is +2 and F is -1
-1 for F +6 for S
+4 Oxygen is with F and then oxygens oxidation number is +2 as F is more electro negative than Oxygen . Here the calculation is (+1x2)+(2x)+(+2x1)+(-2X6)=0
Total electrons --> 7+42-1=48 Cl as a central atom One lone pair on Cl (on the side) 4 F's up and down and the other two on the opposite side of lone pair. F I :- Cl - F - F I F This is the best I can do with plain text.
Cl +5, F -1