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The compound has no charge. This means that the positive oxidation numbers must equal the negative oxidation numbers. 'H' always has an oxidation number of +1. There are three of these atoms in the compound giving +3. To cancel out this positive number, the 'B' must equal -3.

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11y ago
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11y ago

+6 is the answer for boron trifluoride

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11y ago

+2 for Ba, -1 for each F

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Q: What is the oxidation number for BaF2?
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