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Oxidation is the loss of electrons. Plain and simple.

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10y ago

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What is the oxydation state for S in SO4-2?

' +6' To calculate the oxidatioin state. use oxygen at '-2' as the standard. There being four oxygen atoms in SO4^(2-) Then the oxygen moiety is 4 x -2 = -8 Since the overall charge on the anion is ;-2' We create a little sum S + -8 = -2 S - 8 = -2 Add '8' to both sides S = -2 + 8 S = +6 (The oxidation state of sulphur in SO4^(2-) . NB Sulphur has variable oxidation states, ranging from -2,0,2,4, & 6. NNB The oxidation number indicates the number of electrons in the valence(outermost) shell involved in bonding. Not all electrons in the valence shell are used in bonding. This method is good for calculating other oxidation states. e.g. potassium manganate (VII) : KMnO4. What is the oxidation state of manganese. ? It is ;7; (VII). How do we go there> Again remeber oxygen at '-2' and the manganese anion is MnO4^(-) So 4 x -2 = -8 Create the sum Mn + - 8 = -1 (The charge on the anion). Add '8' tpo both sides. Mn = -1 + 8 Mn = 7 (The oxidation state of manganese in MnO4^(-) . NNNB All oxidation numbers are quoted as Roman Numerals. . Hence S is (VI) ' 6' and Mn is (VII) '7'.


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Burning is an oxydation reaction.


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Burning is an oxydation reaction.


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Very probably a reaction of oxydation on the surface.


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To avoid the oxydation of radium (as a metal).


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Iron is not resistant to oxydation and acids.


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burning or oxydation