The oxydation state for S in (SO4)2- is 6.
I'm pretty sure it's -2 because everywhere i look i find the chemical formula as being NaHCO3 and if you add up those oxidation numbers then you get -2.
In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-
Combustion is a an oxydation reaction, a reaction with oxygen.
The polyatomic ion sulfite = SO3-2
The oxidation state of Co in CoCl2 is +2. This is because Cl is more electronegative than Co, causing it to have a 1- charge each. Since there are two Cl atoms, the oxidation state of Co must be +2 to balance the charges.
The oxidation state of S in SO42- is +6. Each oxygen atom has an oxidation state of -2, so the total charge of -2 for sulfate ion requires sulfur to have an oxidation state of +6 to balance the charge.
As SO42- has an overall -2 charge, The Oxygen has a -2 oxidation state, so to balance and give an overall -2 charge, the Sulfur has to have a +6 oxidation state. (-2 x 4) + (s) = -2 s = +6
In S2O82-, each S atom has an oxidation number of +5. In SO42-, the oxidation number of S is also +5. There is no change in oxidation number for sulfur when transitioning from S2O82- to SO42-.
The SO42- ion is named sulfate.
I'm pretty sure it's -2 because everywhere i look i find the chemical formula as being NaHCO3 and if you add up those oxidation numbers then you get -2.
The formal charge of the SO42- ion is -2.
The formal charge of the sulfate ion (SO42-) is -2.
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-
Glucose oxydation
It is called Oxydation
H. Aurich has written: 'Die Oxydation aliphatischer Kohlenwasserstoffe durch Bakterien' -- subject(s): Oxidation, Hydrocarbons, Biodegradation