The oxidation state of Co in CoCl2 is +2. This is because Cl is more electronegative than Co, causing it to have a 1- charge each. Since there are two Cl atoms, the oxidation state of Co must be +2 to balance the charges.
The oxydation state for S in (SO4)2- is 6.
To answer this question you need the molecular weight of CoCl2. CoCl2 molecular weight is 129.84 g/mole 230g CoCl2 divided by the molecular weight 230 g / 129.84 g/mole = 1.77 moles of CoCl2 Multiply the moles by Avagodro's number 1.77 mole * 6.022 X 1023 molecules/mole = 1.07 X 1024 molecules of CoCl2
To calculate the equilibrium partial pressures, we start with the balanced reaction: CO(g) + Cl2(g) ⇌ COCl2(g). Given the initial partial pressures of CO and Cl2 are both ( P_0 ), we can set up an ICE (Initial, Change, Equilibrium) table. At equilibrium, let the change in the concentration of CO and Cl2 be ( -x ), and the change in COCl2 be ( +x ). The equilibrium expression is ( K_p = \frac{P_{COCl2}}{P_{CO} \cdot P_{Cl2}} = 1.57 ). Substituting the equilibrium pressures into the equation and solving for ( x ) allows us to find the equilibrium partial pressures of all species.
I'm pretty sure it's -2 because everywhere i look i find the chemical formula as being NaHCO3 and if you add up those oxidation numbers then you get -2.
To calculate the weight of solid CoCl2 needed, you can use the formula: weight = (molarity) x (volume) x (molar mass) Substitute the values: weight = 0.150 mol/L x 0.5 L x 129.84 g/mol = 9.74 g of CoCl2 is needed.
The oxydation state for S in (SO4)2- is 6.
The chemical reaction is:2 NaOH + CoCl2 = 2 NaCl + Co(OH)2
2hcl
Co + 2HCl -> CoCl2 + H2
The balanced equation for the reaction between cobalt chloride (CoCl2) and ammonia (NH3) would be: CoCl2 + 6NH3 → [Co(NH3)6]Cl2
To answer this question you need the molecular weight of CoCl2. CoCl2 molecular weight is 129.84 g/mole 230g CoCl2 divided by the molecular weight 230 g / 129.84 g/mole = 1.77 moles of CoCl2 Multiply the moles by Avagodro's number 1.77 mole * 6.022 X 1023 molecules/mole = 1.07 X 1024 molecules of CoCl2
Two molecules of cobalt chloride have 2 Co atoms and 4 Cl atoms.
No, CoCl2 has ionic bonds. It is composed of cobalt (Co) which is a metal and chlorine (Cl) which is a non-metal. Ionic bonds form between metals and non-metals, where electrons are transferred from one atom to another.
The molar mass of cobalt chloride (CoCl2) is 129.84 g/mol.
To calculate the equilibrium partial pressures, we start with the balanced reaction: CO(g) + Cl2(g) ⇌ COCl2(g). Given the initial partial pressures of CO and Cl2 are both ( P_0 ), we can set up an ICE (Initial, Change, Equilibrium) table. At equilibrium, let the change in the concentration of CO and Cl2 be ( -x ), and the change in COCl2 be ( +x ). The equilibrium expression is ( K_p = \frac{P_{COCl2}}{P_{CO} \cdot P_{Cl2}} = 1.57 ). Substituting the equilibrium pressures into the equation and solving for ( x ) allows us to find the equilibrium partial pressures of all species.
The gram equivalent weight of CoCl2 is calculated by dividing the molar mass of CoCl2 by its valency. The formula weight of CoCl2 is 129.84 g/mol. Since the valency of CoCl2 is 2, the gram equivalent weight would be 129.84/2 = 64.92 g/equiv.
CoCl2 is an ionic compound. It is made up of cobalt (Co) and chloride (Cl) ions, where the cobalt ion has a charge of +2 and the chloride ions have a charge of -1. Ionic compounds are formed by the transfer of electrons between metal and nonmetal atoms.