The oxidation state of Co in CoCl2 is +2. This is because Cl is more electronegative than Co, causing it to have a 1- charge each. Since there are two Cl atoms, the oxidation state of Co must be +2 to balance the charges.
The oxydation state for S in (SO4)2- is 6.
To answer this question you need the molecular weight of CoCl2. CoCl2 molecular weight is 129.84 g/mole 230g CoCl2 divided by the molecular weight 230 g / 129.84 g/mole = 1.77 moles of CoCl2 Multiply the moles by Avagodro's number 1.77 mole * 6.022 X 1023 molecules/mole = 1.07 X 1024 molecules of CoCl2
To calculate the equilibrium partial pressures, we start with the balanced reaction: CO(g) + Cl2(g) ⇌ COCl2(g). Given the initial partial pressures of CO and Cl2 are both ( P_0 ), we can set up an ICE (Initial, Change, Equilibrium) table. At equilibrium, let the change in the concentration of CO and Cl2 be ( -x ), and the change in COCl2 be ( +x ). The equilibrium expression is ( K_p = \frac{P_{COCl2}}{P_{CO} \cdot P_{Cl2}} = 1.57 ). Substituting the equilibrium pressures into the equation and solving for ( x ) allows us to find the equilibrium partial pressures of all species.
I'm pretty sure it's -2 because everywhere i look i find the chemical formula as being NaHCO3 and if you add up those oxidation numbers then you get -2.
To calculate the weight of solid CoCl2 needed, you can use the formula: weight = (molarity) x (volume) x (molar mass) Substitute the values: weight = 0.150 mol/L x 0.5 L x 129.84 g/mol = 9.74 g of CoCl2 is needed.
The oxydation state for S in (SO4)2- is 6.
The chemical reaction is:2 NaOH + CoCl2 = 2 NaCl + Co(OH)2
2hcl
Co + 2HCl -> CoCl2 + H2
The balanced equation for the reaction between cobalt chloride (CoCl2) and ammonia (NH3) would be: CoCl2 + 6NH3 → [Co(NH3)6]Cl2
To answer this question you need the molecular weight of CoCl2. CoCl2 molecular weight is 129.84 g/mole 230g CoCl2 divided by the molecular weight 230 g / 129.84 g/mole = 1.77 moles of CoCl2 Multiply the moles by Avagodro's number 1.77 mole * 6.022 X 1023 molecules/mole = 1.07 X 1024 molecules of CoCl2
Two molecules of cobalt chloride have 2 Co atoms and 4 Cl atoms.
To calculate the equilibrium partial pressures, we start with the balanced reaction: CO(g) + Cl2(g) ⇌ COCl2(g). Given the initial partial pressures of CO and Cl2 are both ( P_0 ), we can set up an ICE (Initial, Change, Equilibrium) table. At equilibrium, let the change in the concentration of CO and Cl2 be ( -x ), and the change in COCl2 be ( +x ). The equilibrium expression is ( K_p = \frac{P_{COCl2}}{P_{CO} \cdot P_{Cl2}} = 1.57 ). Substituting the equilibrium pressures into the equation and solving for ( x ) allows us to find the equilibrium partial pressures of all species.
No, CoCl2 has ionic bonds. It is composed of cobalt (Co) which is a metal and chlorine (Cl) which is a non-metal. Ionic bonds form between metals and non-metals, where electrons are transferred from one atom to another.
The molar mass of cobalt chloride (CoCl2) is 129.84 g/mol.
The gram equivalent weight of CoCl2 is calculated by dividing the molar mass of CoCl2 by its valency. The formula weight of CoCl2 is 129.84 g/mol. Since the valency of CoCl2 is 2, the gram equivalent weight would be 129.84/2 = 64.92 g/equiv.
CoCl2 is an ionic compound. It is made up of cobalt (Co) and chloride (Cl) ions, where the cobalt ion has a charge of +2 and the chloride ions have a charge of -1. Ionic compounds are formed by the transfer of electrons between metal and nonmetal atoms.