They are both s level orbitals; they can carry two electrons and are spherical in shape. The only difference is that the 4s level is larger than the 3s, and the 3s level will fill first.
4s 3p 3s 2p 1s This is probably one of the easiest chemistry problems in the book, you should probably look it up.
In krypton atoms, the 3s and 3p sublevels are filled, i.e. 3s23p6.
3s and 3p
3s and 3p
There are one 3s orbital, three 3p orbitals, and five 3d sublevels.
4s 3p 3s 2p 1s This is probably one of the easiest chemistry problems in the book, you should probably look it up.
-3s*4p+-4s*3p -12sp+-12sp -24sp
3s and 3p
In krypton atoms, the 3s and 3p sublevels are filled, i.e. 3s23p6.
3s and 3p
3s and 3p
The order for filling in the sublevels becomes; 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d,7p.
the orbitals of the sublevels of the same principal energy level differ in shape which describes where the electron is likely to be found. Also the orbitals of sublevels have different energy levels. In ascending enegy in any level s < p < d < f < g etc HOWEVER whether the different sublevels exist depends on the principal energy level ie 1s 2s, 2p 3s, 3p, 3d 4s, 4p, 4d, 4f
9
4s-5-3s =s-5 The s and 5 can not subtract because they aren't like terms. Like terms have the same variable.
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
2t-4s