The concentration of H3O+ can be calculated using the equation Kw = [H3O+][OH-]. Given that Kw = 1.0 x 10^-14, and [OH-] = 4.54 x 10^-6 M, you can solve for [H3O+] to find that it is approximately 2.2 x 10^-9 M.
To find the OH- concentration in water when you know the H3O+ concentration, you can use the formula Kw = [H3O+][OH-]. Given that Kw (at 25°C) is 1.0 x 10^-14, you can rearrange the equation to solve for OH-. In this case, [OH-] = Kw / [H3O+] which would equal 2.94 x 10^-12 M.
- log(1 X 10 -12 M) = 12 pH -----------------------very little room for H3O
CH3NH3Cl->CH3NH3+ + Cl¯ Cl¯+H2O-> Doesn't reactor! CH3NH3+ +H2O <-> CH3NH2 + H3O+ (c-x) M x M x M H2O + H2O <-> H3O+ + OH¯ y M y M [H3O+]w= (x+y) M [OH¯]= y M Like this: [H3O+]>[OH¯] => Acid
H3O+ concentration in a 0.048 M NaOH solution is 2.4 x 10^-12 M. This is because NaOH is a strong base that dissociates completely in water to produce Na+ and OH- ions, which react with any H3O+ ions to form water. As a result, the H3O+ concentration in such a solution is extremely low.
pH=10, means the concentration of OH- ions is 0.0001 M and concentration of H+ ions is 0.0000000001M
To find the OH- concentration in water when you know the H3O+ concentration, you can use the formula Kw = [H3O+][OH-]. Given that Kw (at 25°C) is 1.0 x 10^-14, you can rearrange the equation to solve for OH-. In this case, [OH-] = Kw / [H3O+] which would equal 2.94 x 10^-12 M.
- log(1 X 10 -12 M) = 12 pH -----------------------very little room for H3O
The concentration of OH- for a solution with H3O+ concentration of 1x10^-5 M can be found by using the ion product constant of water (Kw = 1.0x10^-14) to calculate the OH- concentration. Since H3O+ and OH- are related by Kw = [H3O+][OH-], you can solve for [OH-] by rearranging the equation. This will give you a value of 1.0x10^-9 M for the OH- concentration.
CH3NH3Cl->CH3NH3+ + Cl¯ Cl¯+H2O-> Doesn't reactor! CH3NH3+ +H2O <-> CH3NH2 + H3O+ (c-x) M x M x M H2O + H2O <-> H3O+ + OH¯ y M y M [H3O+]w= (x+y) M [OH¯]= y M Like this: [H3O+]>[OH¯] => Acid
H3O+ concentration in a 0.048 M NaOH solution is 2.4 x 10^-12 M. This is because NaOH is a strong base that dissociates completely in water to produce Na+ and OH- ions, which react with any H3O+ ions to form water. As a result, the H3O+ concentration in such a solution is extremely low.
pH=10, means the concentration of OH- ions is 0.0001 M and concentration of H+ ions is 0.0000000001M
The concentration of H3O+ ions can be calculated using the formula pH = -log[H3O+]. Rearrange the formula to get [H3O+] = 10^(-pH). Plugging in the pH value of 2.32 gives a concentration of H3O+ ions of approximately 4.63 x 10^(-3) M.
3. since the [H+]=0.001 M then pH= -log[H+] -log(0.001)=3 pH=3.
A 1.0 M hydrochloric acid (HCl) solution would have the largest concentration of hydronium ions (H3O+) since each mole of HCl dissociates completely to form one mole of H3O+. This means that the concentration of H3O+ ions in a 1.0 M HCl solution would also be 1.0 M.
The pH of a solution with a H3O+ concentration of 7.9x10-11 M is approximately 10.1. This is because pH is calculated as -log[H3O+], so -log(7.9x10-11) ≈ 10.1.
The molar concentration of [H3O+] in a cola with a pH of 3.120 can be calculated this way: [H3O+] = 10-ph [H3O+] = 10-3.120 [H3O+] = 7.59 x 10-4 M Answer: 7.59 x 10-4 M Ingestion of large amounts of phosphoric acid found in cola can upset the body's regulation of bone metabolism and reduce the absorption of calcium from the diet. For this reason, people who are at risk of developing osteoporosis are often advised not to drink much cola.
By definition: pH = -log[H3O+]So pH = -log(7.4*10-9) = 8.13