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The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.

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Q: What is the OH- of a 4.0 x 10-4 M solution of CaOH2?
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Mass of 24 mole of CaOH2?

1 mole of mass of ca (OH) 2 = 40*1 + (16 + 1) 2 = 40 + 34 = 74g. So, mass of 24 moles = 24*74 = 1776g.


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The OH concentration in a 4.0 x 10^4 M solution of Ca(OH)2 can be determined by dividing the concentration of Ca(OH)2 by its stoichiometric coefficient, which is 2. Thus, the OH concentration is 2.0 x 10^4 M.


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Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed


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Ca(OH)2 is Calcium hydroxide (by chemical name), also known as lime, slaked lime, slack lime or pickling lime (by trivial and geological name)Limewater is the name of saturated solution of it in water.


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m sub Ca(OH)2 = ( 10 g Ca ) [ ( 74.12 g Ca(OH)2 ) / ( 40.078 g Ca) ] m sub Ca(OH)2 = 18.5 g Ca(OH)2 <------------------


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Ca(OH)2 and Mg(OH)2 react with sulfuric acid to form the salts, calcium sulfate and magnesium sulfate respectively


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It is 104 miles according to Google Maps.