The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
Wiki User
∙ 15y agoThe hydroxide ion concentration in a 4.0 x 10^-4 M solution of Ca(OH)2 can be calculated by first finding the molarity of OH- ions from Ca(OH)2, which is twice the molarity of the overall solution. Therefore, the [OH-] is 8.0 x 10^-4 M.
Yes, Ca(OH)2 will precipitate from solution because at a pH of 8.0, the solution is basic enough to cause Ca(OH)2 to form. This is because Ca(OH)2 is more soluble in basic solutions due to the shift in equilibrium towards the formation of the hydroxide ions.
The OH concentration in a 4.0 x 10^4 M solution of Ca(OH)2 can be determined by dividing the concentration of Ca(OH)2 by its stoichiometric coefficient, which is 2. Thus, the OH concentration is 2.0 x 10^4 M.
Calcium hydroxide is written as Ca(OH)2 because the hydroxide ion (OH-) is a polyatomic ion composed of one oxygen atom and one hydrogen atom. In the compound, there are two hydroxide ions associated with one calcium ion, which is why it is written as Ca(OH)2 and not CaOH2.
4N NaOH refers to a solution of sodium hydroxide (NaOH) with a concentration of 4 normal (4N). This means that the solution contains 4 moles of NaOH dissolved in 1 liter of solution. Normality is a unit of concentration that is used in acid-base chemistry to express the number of equivalents of a substance per liter of solution.
Ca(OH)2 is a base because it produces hydroxide ions (OH-) in solution. It is formed by the reaction of calcium oxide (CaO) with water.
Yes, Ca(OH)2 is a strong base. When it dissolves in water, it releases hydroxide ions (OH-) which can accept protons to form water, making the solution basic.
Yes, Ca(OH)2 will precipitate from solution because at a pH of 8.0, the solution is basic enough to cause Ca(OH)2 to form. This is because Ca(OH)2 is more soluble in basic solutions due to the shift in equilibrium towards the formation of the hydroxide ions.
To find the pH of the solution, first calculate the moles of OH- from each solution (Ca(OH)2 and NaOH). Then, add the moles of OH- together and calculate the total volume of the combined solutions. Finally, use the concentration of OH- ions in the combined solution to calculate the pOH and pH of the solution.
The OH concentration in a 4.0 x 10^4 M solution of Ca(OH)2 can be determined by dividing the concentration of Ca(OH)2 by its stoichiometric coefficient, which is 2. Thus, the OH concentration is 2.0 x 10^4 M.
Ca(OH)2 and Na2O
2 moles of Ca and 4 moles of OH
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
Calcium hydroxide is written as Ca(OH)2 because the hydroxide ion (OH-) is a polyatomic ion composed of one oxygen atom and one hydrogen atom. In the compound, there are two hydroxide ions associated with one calcium ion, which is why it is written as Ca(OH)2 and not CaOH2.
4N NaOH refers to a solution of sodium hydroxide (NaOH) with a concentration of 4 normal (4N). This means that the solution contains 4 moles of NaOH dissolved in 1 liter of solution. Normality is a unit of concentration that is used in acid-base chemistry to express the number of equivalents of a substance per liter of solution.
Ca(OH)2 is a base because it produces hydroxide ions (OH-) in solution. It is formed by the reaction of calcium oxide (CaO) with water.
The molecular weight of Ca(OH)2 (calcium hydroxide) is approximately 74.09 g/mol.
It is 104 miles according to Google Maps.