You take the 52.3g and divide it by the Atomic Mass of the element, 44.95 (varies depending on Periodic Table) and you get 1.16 mol
Uranium price is 115 USD/kg for the unrefined oxide U3O8, in August 2011. 1 international ounce = 28,349 523 125 g; 1 kg = 1 000 g.
The molarity of a solution containing 7.0 moles of solute in 569mL of solution is a)81M b)0.081M c)12M D)4.0M The answer is C. 12M 7 x 1000/569 = 12.302
Tollen's test is an old oxidation reaction in which the oxidizing agent is a complex cation, diamminesilver(I), (NH3)2Ag+, and the reducing agent is probably the anion of an aldehyde hydrate, which for formaldehyde could be written as HOCH2-O(-). The mechanism is probably not known; a literature search I just performed turned up no immediately useful hits. Historically, the two front-runners for the likely mechanism are single-electron-transfer (SET) and hydride abstraction by diaminosilver(I). These two processes turn up in most oxidation mechanisms involving an electron-rich CH bond (as the one in the aldehyde hydrate) and an electron-poor metal cation. SET involves direct transfer of an electron from the molecular orbital closely tied to the C-H bond about to be broken, to the silver ion. Hydride abstraction involves a favorable collision between the silver ion and the aldehyde hydrate in which H- (the hydride ion) is transferred to the silver, leaving HOCH(+)-O(-) behind, which is essentially just a resonance structure for formic acid, HOCHO. The fate of the newly formed silver-hydride bond is almost certainly the release of a hydronium ion, leaving behind a neutral silver ion. The mechanism would have to explain why benzaldehyde reacts almost instantly, while sugars and branched-chain aldhydes react slowly, for example, as well as why siilver carbonate, Ag2CO3, supported on celite oxidizes alcohols to aldehydes and stops (J. Org. Chem, 1974, vol 39, p. 523), but Tollen's test conditions oxidize aldehydes (not alcohols) to acids, among other experimental observations.
52300%523:= 523 * 100%= 52300%
194 + 329 = 523. Found by subtracting 329 from 523. 523 - 329 = 194.
It is 523 times 1 = 523 which is a prime number
523 x 18 = (523 x 10) + (523 x 8)
4t-523 = -519
As a fraction: 0.523 = 523/1000
2x-523 = -521
523
523 is not divisible by four because four does not go into 523 evenly.
-5.23 = -523/100 and simplifies to: -523/100
436 + 523 = 959
1 and 523, as it is a prime number.