__H2SO4(aq)+ __NaOH(aq)=?
H2SO4 is a strong acid, and NaOH is a strong base. Those facts you just have to memorize. There aren't a lot of strong acids and bases, so it's easy to remember them. Strong acid means that the substance completely dissociates in aqueous solution, so in water, H2SO4 exists as two species, H+ and HSO4-. HSO4- is a weak acid, so it will exist in three species, HSO4- H+ and SO4-2. As a strong base, NAOH will completely dissociate in water, meaning it exists as Na+ and OH-.
Acid/base neutralization reactions always produce a salt and water. The ionic equation is:
_H+(aq)+_SO4-2(aq)+ _Na+(aq)+_OH-(aq)=__H2O(l)+_Na2SO4(s)
2H+(aq)+SO4-2(aq)+2Na+(aq)+2OH-(aq)=2H2O(l)+Na2SO4(s)
This is also the net ionic because there is no species on the left side of the equation that remains the same on the right side of the equation.
It can also be written:
H2SO4(aq)+ 2NaOH(aq) = 2H2O(l) + Na2SO4(s)
To balance the reaction between NaOH and H2SO4, you first write out the unbalanced equation: NaOH + H2SO4 -> Na2SO4 + H2O. To balance it, you need to ensure the same number of atoms of each element on both sides of the equation by adjusting the coefficients. In this case, you would need to put a coefficient of 2 in front of NaOH to balance the equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
The balanced chemical equation for the reaction is H2SO4 + 2NaOH -> Na2SO4 + 2H2O. From the mole ratio, 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the volume and concentration of NaOH, we can calculate the moles of NaOH used. Then, knowing the moles of NaOH used and the volume of H2SO4, we can find the concentration of sulfuric acid.
To balance the reaction between NaOH and H2SO4, you first write out the unbalanced equation: NaOH + H2SO4 -> Na2SO4 + H2O. To balance it, you need to ensure the same number of atoms of each element on both sides of the equation by adjusting the coefficients. In this case, you would need to put a coefficient of 2 in front of NaOH to balance the equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
The balanced chemical equation for the reaction is H2SO4 + 2NaOH -> Na2SO4 + 2H2O. From the mole ratio, 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the volume and concentration of NaOH, we can calculate the moles of NaOH used. Then, knowing the moles of NaOH used and the volume of H2SO4, we can find the concentration of sulfuric acid.
Drain cleaners typically contain sodium hydroxide (NaOH) or sulfuric acid (H2SO4) as the active ingredient. The chemical equation for sodium hydroxide acting as a drain cleaner is: NaOH + H2O -> Na+ + OH- + H2O. Sulfuric acid's equation as a drain cleaner would be: H2SO4 + H2O -> H3O+ (hydronium ion) + HSO4- (bisulfate ion).
i dont know so help
Sulfuric acid plus sodium hydroxide gives sodium sulfate plus water.
To produce 200 g of Na2SO4, you would need 80 g of NaOH (sodium hydroxide) and 98 g of H2SO4 (sulfuric acid) based on their respective molar masses and stoichiometry in the balanced chemical equation for the reaction.
To balance the reaction between H3PO4 and NaOH, first write out the chemical equation: H3PO4 + 3 NaOH -> Na3PO4 + 3 H2O Now, each element must have the same number of atoms on both sides of the equation for it to be balanced. Adjust the coefficients in front of each compound to achieve this balance.
2 NaOH + SO2 = H2O + Na2SO3
Well, darling, if we're talking about a 1:2 molar ratio between NaOH and H2SO4, then you'd need 2 moles of NaOH to neutralize 1 mole of H2SO4. It's all about those stoichiometry dance moves, honey. Just make sure you're not tripping over your chemical equations!