The balanced equation would beNa + Cl -> NaCl
Basically this reaction can be done by plunging a piece of sodium into a glass gas filled with chlorine gas. A lot of heat is produced in this reaction.
The balanced ionic equation for sodium chloride (NaCl) in water (H2O) is: NaCl (s) → Na+ (aq) + Cl- (aq) This equation shows the dissociation of sodium chloride into its ions sodium (Na+) and chloride (Cl-) in water.
The balanced reaction between sodium and chlorine is as follows Na + Cl =>Na+ + Cl-. In this reaction, sodium loses an electron to sodium. Note that the products of this reaction are ions in the solid state.
To balance the equation Cl₂ + 2NaI -> 2NaCl + I₂ you need to ensure that the number of each element is the same on both sides of the equation. In this case, you balance the equation by adding a coefficient of 2 in front of NaCl and I₂ to balance the number of atoms of Na, Cl, and I.
The net ionic equation for Na^+ + Cl^- is Na^+ + Cl^- → NaCl, which represents the formation of sodium chloride when Na^+ and Cl^- ions combine. This equation shows the reactants and products without including spectator ions that do not participate in the reaction.
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
The balanced ionic equation for sodium chloride (NaCl) in water (H2O) is: NaCl (s) → Na+ (aq) + Cl- (aq) This equation shows the dissociation of sodium chloride into its ions sodium (Na+) and chloride (Cl-) in water.
The balanced reaction between sodium and chlorine is as follows Na + Cl =>Na+ + Cl-. In this reaction, sodium loses an electron to sodium. Note that the products of this reaction are ions in the solid state.
The equation is: NaCl----------Na++ Cl-
To balance the equation Cl₂ + 2NaI -> 2NaCl + I₂ you need to ensure that the number of each element is the same on both sides of the equation. In this case, you balance the equation by adding a coefficient of 2 in front of NaCl and I₂ to balance the number of atoms of Na, Cl, and I.
The net ionic equation for Na^+ + Cl^- is Na^+ + Cl^- → NaCl, which represents the formation of sodium chloride when Na^+ and Cl^- ions combine. This equation shows the reactants and products without including spectator ions that do not participate in the reaction.
2NaCl + F2 -> 2NaF + Cl2 The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
The original equation is Na + Cl = NaCl. The thing is, chlorine is one of 7 elements that doesn't like to be alone, so it's always 'Cl2', making the equation Na + Cl2 = NaCl. However, this is no longer balanced. So what you do is add a '2' onto NaCl, making it Na + Cl2 = 2NaCl. Now the chlorine is balanced, but the sodium isn't. After that, to balance the sodium, you add a '2' in front of 'Na' making the equation 2Na + Cl2 = 2NaCl.
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Here is the balanced equation! TiCl4 + 2H2O --> TiO2 + 4HCl
2Fe+3Cl2------>2FeCl3
Sodium chloride doesn't react with water. Sodium chloride is dissolved and dissociated in water: NaCl---------------→Na+ + Cl-
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think