The chemical formula for it is PbI2, but to have an equation there must be another reactant or specified phase.
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
The balanced equation for cesium iodide is CsI(s) → Cs+(aq) + I^-(aq) when it is dissolved in water.
A precipitate of Lead iodide and Potassium nitrate are formed
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
The balanced equation for cesium iodide is CsI(s) → Cs+(aq) + I^-(aq) when it is dissolved in water.
A precipitate of Lead iodide and Potassium nitrate are formed
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
The balanced equation for the formation of silver iodide is: 2 AgNO3 + 2 KI → 2 AgI + 2 KNO3
The balanced equation for the reaction of aluminum and iodine to form aluminum iodide is: 2Al + 3I2 -> 2AlI3
Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
Balanced:H2 + I2 ----> 2 HI
The balanced equation for fluorine reacting with sodium iodide is: 2 NaI + F2 → 2 NaF + I2