I think it's:
Mg2 (s) + Fe (NO3)3 (l) -> MgNO2 + Fe3
Mg+Ba(NO3)2--->MgO+BaO+NO2
Balance it yourself =)
Magnesium, being more reactive than iron, displaces iron from iron(III) carbonate to form magnesium carbonate. The reaction takes place as follows:
3Mg + Fe2(CO3)3 → 2Fe + 3MgCO3
Mg (s) + 2 HNO3 (aq) --> H2 (g) + Mg(NO3)2 (aq)
Mg + 2 HCl = MgCl2 + H2
In a chemical equation ,we must finish our chemical reaction with as many atoms of each element as when we started.the balanced chemical equation for the reaction of solid magnesium metal and barium chloride is given as .Mg + Bacl 2 -> Mgcl2 + Ba.
Magnesium is not polyvalent so you do not need to specify Magnesium 2 or II.The formula for magnesium nitrate is Mg(NO3)2If you had intended to ask the formula for manganese (II) nitrate, it is Mn(NO3)2
3Mg (s) + 2Al3+ (aq) ---> 3Mg2+ (aq) + 2Al (s)
2Mg + O2 → 2MgO
2Mg + O2 >> 2MgO
Mg (s) + 2 HNO3 (aq) --> H2 (g) + Mg(NO3)2 (aq)
soz me dont know
If the copper nitrate formed is copper (I) nitrate, the equation balances with one atom of each metal and one formula weight of each nitrate. If the copper nitrate formed is copper (II) nitrate, the balanced equation is: 2 AgNO3 + Cu -> 2 Ag + Cu(NO3)2.
Mg + 2 HCl = MgCl2 + H2
2Mg(s) + O2(g) -> MgO(s)
In a chemical equation ,we must finish our chemical reaction with as many atoms of each element as when we started.the balanced chemical equation for the reaction of solid magnesium metal and barium chloride is given as .Mg + Bacl 2 -> Mgcl2 + Ba.
Magnesium is not polyvalent so you do not need to specify Magnesium 2 or II.The formula for magnesium nitrate is Mg(NO3)2If you had intended to ask the formula for manganese (II) nitrate, it is Mn(NO3)2
Fe(s) + 3AgNO3 ==> Fe(NO3)3 + 3Ag(s)
3Mg (s) + 2Al3+ (aq) ---> 3Mg2+ (aq) + 2Al (s)
This reaction can occur according to the equation Cu + AgNO3 = CuNO3 + Ag or according to the equation Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag, depending on whether Cu(I) or Cu(II) nitrate is formed.