If the copper nitrate formed is copper (I) nitrate, the equation balances with one atom of each metal and one formula weight of each nitrate. If the copper nitrate formed is copper (II) nitrate, the balanced equation is:
2 AgNO3 + Cu -> 2 Ag + Cu(NO3)2.
NH4NO3 (aq) N2O (g) + 2H2O (l)
The P.H. of Ammonium Nitrate is 7(neutral). Why? Now that's a good question. It is on 7 because it is an acid mixed with and alkali which is known as a Neutralization reaction. That is why it is 7 on the P.H. scale. The equation is Ammonium Hydroxide+Nitric Acid which equals to Ammonium Nitrate.
Yes, of course: 4 (NH4)3PO4 + 3 Pb(NO3)4 -> Pb3(PO4)4 + 12 NH4NO3 for lead (IV) nitrate and 2 (NH4)3PO4 + 3 Pb(NO3)2 -> Pb3(PO4)4 + 6 NH4NO3 for lead (II) nitrate.
The law of conservation of mass means that the same number of each atom must be present on both sides of the equation, so that the mass of the reactants equals the mass of the products.
Hg(NH4)2 + SO4(NO3)2
Yes, but your formula for copper II nitrate is incorrect. It should be Cu(NO3)2. The correct equation is Cu(NO3)2 + 2HCl --> CuCl2 + 2HNO3.
Silver nitrate and sodium phosphate react to form silver phosphate and sodium nitrate. The balanced equation is 3 AgNO3(aq) + Na3PO4(aq) equals Ag3PO4(s) + 3 NaNO3(aq).
its already balanced
AgNO3+NaBr--->NaNO3+AgBr
2NaNO3 ==> 2NaNO2 + O2
Wrong ! ! ! ! !Silver + Nitric Acid -----> Silver Nitrate + Water + Nitrogen DioxideAg + 2 HNO3 -----> AgNO3 + H2O + NO2
NaCl+AgNO3=NaNO3+AgCl Because all the elements in this equation have a +1 or -1 charge, no coefficents are needed
Ca(SO3)
Copper sulfate is a reactant in the equation as stated, because it is present before the reaction has occurred and no longer present afterward.
It is already balanced
3h2 + n2 ==> 2nh3
6AG + N2 --> 2AG3N is the balanced equation.