2AgNO3 + ZnI2 -> 2AgI + Zn(NO3)2
Zinc Nitrate + Silver (Displacement Reaction= Zinc is more reactive than Silver)
If the reaction is stoichiometric, 1.30 moles of zinc will generate an equal number of moles of silver. This is based on the balanced chemical equation for the reaction between zinc and silver nitrate.
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
The equation should be: 2AgNO3 + ZnCl2 → 2AgCl + Zn(NO3)2. This means that the number in front of silver nitrate (AgNO3) is 2.
Yes, zinc will react with silver nitrate solution. This reaction occurs because zinc is more reactive than silver, so zinc displaces silver from the silver nitrate solution to form zinc nitrate and silver metal.
Zinc Nitrate + Silver (Displacement Reaction= Zinc is more reactive than Silver)
If the reaction is stoichiometric, 1.30 moles of zinc will generate an equal number of moles of silver. This is based on the balanced chemical equation for the reaction between zinc and silver nitrate.
harish + sheshardri = chochalte
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
The equation should be: 2AgNO3 + ZnCl2 → 2AgCl + Zn(NO3)2. This means that the number in front of silver nitrate (AgNO3) is 2.
Yes, zinc will react with silver nitrate solution. This reaction occurs because zinc is more reactive than silver, so zinc displaces silver from the silver nitrate solution to form zinc nitrate and silver metal.
P = CqB^2
zinc + nitric acid --> zinc nitrate + water and hydrogen I think...
This is a single replacement reaction. Zinc is more reactive than copper, so it replaces it and bonds with sulfate. The balanced equation is Zn + CuSO4 => Cu + ZnSO4 (zinc always has a charge of +2)
The reaction between zinc nitrate and sodium carbonate results in the formation of zinc carbonate, sodium nitrate, and water. The balanced chemical equation for this reaction is: Zn(NO3)2 + Na2CO3 → ZnCO3 + 2NaNO3
Zinc iodide and silver nitrate react to produce zinc nitrate and silver iodide. The balanced chemical equation for this reaction is: ZnI2 + 2AgNO3 → 2AgI + Zn(NO3)2. Silver iodide is a yellow precipitate that forms when the two solutions are mixed.
The balanced equation for zinc nitrate (Zn(NO3)2) and ferrous sulfate (FeSO4) is: Zn(NO3)2 + FeSO4 -> ZnSO4 + Fe(NO3)2.