Oooh, this is a tricky one; as aluminum takes a 3+ charge and the sulphate (UK sulphate = USA sulfate!) a 2- negative. I think barium is 2+ (my chemistry was a while ago). My attempt would be:
Al2(SO4)3 + 3 Ba --> 3 BaSO4 + 2 Al
The balanced chemical equation for the reaction between aluminum and copper sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
The balanced equation for the reaction between aluminum and copper(II) sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
The reaction between aluminum sulfate and ammonia forms aluminum hydroxide and ammonium sulfate. The balanced chemical equation is: Al2(SO4)3 + 6NH3 + 6H2O → 2Al(OH)3 + 3(NH4)2SO4.
In this reaction, aluminum metal reacts with sulfuric acid to produce aluminum sulfate solution and hydrogen gas. The balanced chemical equation for this reaction is: 2Al + 3H2SO4 -> Al2(SO4)3 + 3H2.
To find the amount of copper (II) sulfate needed to react with 0.48 mol of aluminum (III) sulfate, start by writing a balanced chemical equation for the reaction between the two salts. From the balanced equation, determine the molar ratio between copper (II) sulfate and aluminum (III) sulfate. Then, use this ratio to calculate the amount of copper (II) sulfate needed to produce 0.48 mol of aluminum (III) sulfate.
The balanced chemical equation for the reaction between aluminum and copper sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
The balanced equation for the reaction between aluminum and copper(II) sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
The reaction between aluminum sulfate and ammonia forms aluminum hydroxide and ammonium sulfate. The balanced chemical equation is: Al2(SO4)3 + 6NH3 + 6H2O → 2Al(OH)3 + 3(NH4)2SO4.
The balanced equation for the reaction between aluminum and copper (II) sulfate is: 2Al(s) + 3CuSO₄(aq) -> Al₂(SO₄)₃(aq) + 3Cu(s).
In this reaction, aluminum metal reacts with sulfuric acid to produce aluminum sulfate solution and hydrogen gas. The balanced chemical equation for this reaction is: 2Al + 3H2SO4 -> Al2(SO4)3 + 3H2.
To find the amount of copper (II) sulfate needed to react with 0.48 mol of aluminum (III) sulfate, start by writing a balanced chemical equation for the reaction between the two salts. From the balanced equation, determine the molar ratio between copper (II) sulfate and aluminum (III) sulfate. Then, use this ratio to calculate the amount of copper (II) sulfate needed to produce 0.48 mol of aluminum (III) sulfate.
The chemical equation for the reaction when copper is added to aluminum sulfate is: 3Cu + 2Al2(SO4)3 -> 3CuSO4 + 2Al
The reaction between aluminum foil and copper(II) sulfate results in the displacement of copper by aluminum, forming aluminum sulfate and copper metal as products. The balanced chemical equation for this reaction is: 3CuSO4 + 2Al -> Al2(SO4)3 + 3Cu.
Its NOT a balanced Equation ,but a FORMULA. Al2(SO4)3 NB A balanced equation is for two or more reacting substances and their respective products.
no reaction between ammonium sulphate and iron sulphate
When aluminum is added to copper sulfate, a single displacement reaction occurs where the aluminum replaces the copper in the compound to form aluminum sulfate and copper metal. This reaction is represented by the equation: 2Al(s) + 3CuSO4(aq) -> Al2(SO4)3(aq) + 3Cu(s).
The reaction equation for hydrogen sulfate (H2SO4) and aluminum hydroxide (Al(OH)3) is: 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O