Its NOT a balanced Equation ,but a FORMULA.
Al2(SO4)3
NB A balanced equation is for two or more reacting substances and their respective products.
This equation is 3 BaCl2 + Al2(SO4)3 -> 3 Ba(SO4) + 2 AlCl3.
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
The balanced chemical equation for copper sulfate is: CuSO4 + H2O → CuSO4•5H2O
no reaction between ammonium sulphate and iron sulphate
The balanced equation for the decomposition of aluminum oxide is: 2Al2O3(s) → 4Al(s) + 3O2(g)
This equation is 3 BaCl2 + Al2(SO4)3 -> 3 Ba(SO4) + 2 AlCl3.
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
CuSO4 * 5H2O
The balanced chemical equation for copper sulfate is: CuSO4 + H2O → CuSO4•5H2O
no reaction between ammonium sulphate and iron sulphate
The balanced equation for the reaction of aluminum and iodine to form aluminum iodide is: 2Al + 3I2 -> 2AlI3
The balanced equation for the decomposition of aluminum oxide is: 2Al2O3(s) → 4Al(s) + 3O2(g)
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO -> 3Cu + Al2O3.
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO → 3Cu + Al2O3. This reaction produces copper and aluminum oxide.
Oooh, this is a tricky one; as aluminum takes a 3+ charge and the sulphate (UK sulphate = USA sulfate!) a 2- negative. I think barium is 2+ (my chemistry was a while ago). My attempt would be:Al2(SO4)3 + 3 Ba --> 3 BaSO4 + 2 Al
This equation is: 3 BaCl2 (aq) + Al2(SO4)3 (aq) = 3 BaSO4 (s) + 2 AlCl3 (aq).
Barium sulphate to barium sulphate is NO CHANGE!