There shall be none as both compounds have same anions (Nitrates)
barium nitrate + sulphuric acid gives barium sulphate equation is BaNo3 + SO4 - BaSO4
(NH4)2SO4 + Ba(NO3)2 -> BaSO4 + 2NH4NO3
The reaction is:Ba(NO3)2 + K2C2O4 = BaC2O4(s) + 2 KNO3
The balanced chemical equation for the reaction between barium bromide (BaBr2) and lead(II) nitrate (Pb(NO3)2) is: BaBr2 + Pb(NO3)2 -> 2PbBr2 + Ba(NO3)2
NH4+ and NO3- don't react, Only SO42- and Ba2+ do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
barium nitrate + sulphuric acid gives barium sulphate equation is BaNo3 + SO4 - BaSO4
(NH4)2SO4 + Ba(NO3)2 -> BaSO4 + 2NH4NO3
The reaction is:Ba(NO3)2 + K2C2O4 = BaC2O4(s) + 2 KNO3
The balanced chemical equation for the reaction between barium bromide (BaBr2) and lead(II) nitrate (Pb(NO3)2) is: BaBr2 + Pb(NO3)2 -> 2PbBr2 + Ba(NO3)2
The balanced chemical equation for the reaction between barium nitrate and sodium hydroxide is: Ba(NO₃)₂ + 2NaOH → Ba(OH)₂ + 2NaNO₃
When barium nitrate and iron react, they undergo a single displacement reaction. The iron replaces the barium in the nitrate ion, forming iron(II) nitrate and barium as products. The chemical equation for this reaction is: Fe + Ba(NO3)2 -> Fe(NO3)2 + Ba.
The balanced chemical equation for the reaction between barium nitrate (Ba(NO3)2) and potassium hydroxide (KOH) is: Ba(NO3)2 + 2KOH -> Ba(OH)2 + 2KNO3
NH4+ and NO3- don't react, Only SO42- and Ba2+ do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
The chemical reaction between barium nitrate (Ba(NO3)2) and manganese(II) sulfate (MnSO4) will result in barium sulfate (BaSO4) and manganese(II) nitrate (Mn(NO3)2) as products. The balanced equation for this reaction is: Ba(NO3)2 + MnSO4 → BaSO4 + Mn(NO3)2.
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
When copper sulfate reacts with barium nitrate, a double displacement reaction occurs, leading to the formation of insoluble barium sulfate and soluble copper nitrate. The balanced chemical equation for this reaction is CuSO4 + Ba(NO3)2 -> BaSO4 + Cu(NO3)2.
The balanced chemical equation for the reaction between barium acetate and potassium iodide is: Ba(CH3COO)2 + 2KI -> BaI2 + 2KCH3COO